Focal length of plano convex lens

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SUMMARY

The focal length of a plano-convex lens with a diameter of 6 cm and a thickness of 3 mm is calculated to be 30 cm. This calculation utilizes the lensmaker's formula for thin lenses, where the radius of curvature (R) is determined to be 15 cm based on the given parameters. The refractive index of the lens material is 1.5, and the speed of light in the material is 2 x 10^8 m/sec. The solution confirms the accuracy of the focal length derived from the provided data.

PREREQUISITES
  • Understanding of the lensmaker's formula for thin lenses
  • Knowledge of basic optics concepts such as focal length and refractive index
  • Familiarity with the properties of plano-convex lenses
  • Ability to perform calculations involving geometry and optics
NEXT STEPS
  • Study the derivation and applications of the lensmaker's formula
  • Explore the differences between plano-convex and biconvex lenses
  • Learn about the impact of refractive index on lens performance
  • Investigate practical applications of plano-convex lenses in optical devices
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Optics students, optical engineers, and anyone involved in designing or utilizing lenses in optical systems will benefit from this discussion.

Amith2006
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# Diameter of a Plano-convex lens is 6 cm and the thickness at the center is 3 mm. If the speed of light in the material of the lens is 2 x 10^8 m/sec, what is the focal length of the lens?
I solved it in the following way:
Let R be the radius of curvature of the convex surface.
Given that AB = 3 mm = 0.3 cm, AD = CD/2 = 3 cm, refractive index(n) = 1.5
By the property of circles,
AB = (AD^2)/(2R)
Therefore, R = (AD^2)/(2AB)
= 9/(2 x 0.3)
= 15 cm
According to thin lens formula,
1/f = (n – 1)/R
Solving I get,
f = 30 cm
Is it right?
 

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Amith2006 said:
# Diameter of a Plano-convex lens is 6 cm and the thickness at the center is 3 mm. If the speed of light in the material of the lens is 2 x 10^8 m/sec, what is the focal length of the lens?
I solved it in the following way:
Let R be the radius of curvature of the convex surface.
Given that AB = 3 mm = 0.3 cm, AD = CD/2 = 3 cm, refractive index(n) = 1.5
By the property of circles,
AB = (AD^2)/(2R)
Therefore, R = (AD^2)/(2AB)
= 9/(2 x 0.3)
= 15 cm
According to thin lens formula,
1/f = (n – 1)/R
Solving I get,
f = 30 cm
Is it right?
Yes. For the benefit of others, you are using the lensmaker's forumula for thin lenses, not to be confused with the thin lens equation.

AM
 
Thanks for your help.
 

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