For a solution that contains 0.10 M HCN and 0.10 M NaCN, whi

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SUMMARY

The discussion centers on a solution containing 0.10 M HCN and 0.10 M NaCN, analyzing which statement regarding the solution is false. The participants identify that the acid is HCN and the conjugate base is NaCN, with a 1:1 concentration ratio. They conclude that the addition of NaOH will shift the equilibrium to the right, increasing [NaCN], while the common ion effect is relevant in this context. Ultimately, the false statement is identified as (C), which incorrectly asserts that [H+] is equal to Ka.

PREREQUISITES
  • Understanding of the common ion effect in chemistry
  • Knowledge of acid-base equilibrium and Le Chatelier's principle
  • Familiarity with the concept of conjugate acids and bases
  • Basic skills in writing chemical equations and equilibrium expressions
NEXT STEPS
  • Study the common ion effect in detail
  • Learn about acid-base equilibria and how to calculate pH
  • Explore Le Chatelier's principle and its applications in chemical reactions
  • Review the derivation and use of the acid dissociation constant (Ka)
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Chemistry students, educators, and anyone studying acid-base reactions and equilibrium concepts will benefit from this discussion.

JessicaHelena
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Homework Statement



>For a solution that contains 0.10 M HCN and 0.10 M NaCN, which statement is false?
A) This is an example of the common ion effect.
B) The [H+] is larger than it would be if only the HCN was in solution.
C) the [H+] is equal to $K_a$
D) Addition of more NaCN will shift equilibrium to the left
E) Addition of NaOH will increase [CN^-] and decrease [HCN]

Homework Equations

The Attempt at a Solution


I was actually stumped when I first saw the question. I tried wirintg the equation HCN + NaOH --> NaCN + H2O, and made an ice table so to get (0.1 + x)x/(0.1-x), but I wasn't sure where to go after that.
 
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No need for any calculations here, it is about understanding what is going on.

Can you name the acid and the conjugate base? What is ratio of their concentrations?
 
@Borek — The acid is HCN and the conj base NaCN, and the concentrations have ratios of 1:1
 
This is an important special case. You have mentioned various ions. Can you write an equation for the reaction Involving the ions that you have mentioned? Then an expression for the Ka that you have mentioned.
 
@epenguin
I think HCN + NaOH --> H2O + NaCN could work.

then Ka = [H2O][0.10] / [NaOH][0.10] = [H2O]/[NaOH].so,
for (A), I'm not sure what the common ion effect is so I can't say.
(B) I'm not sure what this is talking about. But I think [H+] would be larger when only HCN is in the solution (bc then there won't be any bases like NaOH), if I understand it right, so this looks like it could be false.
(C) I can't say bc of the [NaOH] in the denominator.
(D) yes, by Le Chatelier's principle, so rule this out.
from the equation, for (E), the addition will shift equilibrium to right so [NaCN] increases and the statement is true, so eliminate this.
 
There are no ions in your #5. Yet they appear in #1
 
what do you mean by #5 and #1?
 
Look at the blue strip above this text. This is #8
 
JessicaHelena said:
what do you mean by #5 and #1?

Post number in the thread.
 

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