Force and acceleration of a traveling proton in a magentic field

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SUMMARY

A proton traveling at a velocity of 2.0 x 106 m/s perpendicular to a magnetic field of 2.0 T experiences a force calculated using the Lorentz force law, specifically F = qvB. Given that the charge of a proton is approximately 1.6 x 10-19 C, the force exerted on the proton is 6.4 x 10-13 N. The acceleration can be determined using Newton's second law, F = ma, where the mass of a proton is approximately 1.67 x 10-27 kg, resulting in an acceleration of approximately 3.83 x 1014 m/s2.

PREREQUISITES
  • Understanding of the Lorentz force law
  • Basic knowledge of electromagnetism
  • Familiarity with Newton's second law (F = ma)
  • Knowledge of fundamental particle properties, specifically protons
NEXT STEPS
  • Study the derivation and applications of the Lorentz force law
  • Explore the relationship between magnetic fields and charged particle motion
  • Learn about the effects of varying magnetic field strengths on particle trajectories
  • Investigate advanced topics in electromagnetism, such as electromagnetic waves
USEFUL FOR

Physics students, educators, and researchers interested in particle dynamics in magnetic fields, particularly those studying electromagnetism and charged particle behavior.

Crichar1
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What force and acceleration would a proton experience if it has a velocity of 2. 106 m/s perpendicular to a magnetic field of 2.0 T?

force: ________ N
acceleration: _______ m/s2



Homework Equations



F = ma
Frictional force = uk(n)
Acceleration=force divided by mass.
 
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Are you familiar with the Lorentz force-law, the magnetic component of the force being F=qvB?
 


To find the force on a charge due to electric and magnetic fields, use F = q(E + v x B).
 

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