(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

20. A 873-kg (1930 lb) dragster, starting from rest, attains a speed of 26.3 m/s (58.9mph) in 0.59 s.

-----a. Find the average acceleration of the dragster during this time interval.

My solution:

Given variables:

M=873kg

Vo=0

Starting time: 0

V=26.3m/s

T=0.59

Formula to be used: V=Vo + at converted into A=v-vo/t

It equals:

a= 26.3/0.59=44.6m/s^2

-----b. What is the magnitude of the average net force on the dragster during this time?

My solution:

Given variables:

m=873 kg

a=44.6m/s^2

F net= ma

F net = 38,935.8 N

F net = 39,900N

-----c. Assume that the driver has a mass of 68kg. What horizontal force does the seat exhert on the driver?

Here is where i have a problem..[B/]

I would assume I have to do:

F net=ma using 68kg as my M and 44.6m/s as my A to solve for the force exherted by the seat, which would equal 1,788.4N (Horizontal Force seat exherts) Yet I dont know if thats done correctly.. I would love someone to revise over the work, especially C to see if I did it correctly..

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# Force and Motion, horizontal forces

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