Force between charges and dielectrics

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SUMMARY

The force between two point charges, each with charge q located at positions x=-d and x=d, is calculated using the formula F = q²/(4π(ε₀)4d²). When a dielectric material with dielectric constant K is inserted between the charges, the electric displacement field D remains unaffected by the dielectric, leading to the conclusion that the electric field E remains unchanged. Consequently, the force between the charges remains the same despite the presence of the dielectric, confirming that the dielectric does not alter the force in this specific configuration.

PREREQUISITES
  • Understanding of Coulomb's Law
  • Familiarity with electric fields and electric displacement fields
  • Knowledge of dielectric materials and their properties
  • Basic grasp of electrostatics and charge interactions
NEXT STEPS
  • Study the effects of different dielectric constants on electric fields
  • Explore the relationship between electric displacement field D and electric field E
  • Investigate the role of dielectrics in capacitor design and performance
  • Learn about boundary conditions in electrostatics involving dielectrics
USEFUL FOR

Students and professionals in physics, electrical engineering, and materials science who are interested in electrostatics, charge interactions, and the effects of dielectrics on electric fields.

shomey
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suppose I have a charge q at (x=-d) and a charge q at (x=+d).
the force between them is q^2/(4*pi*(eps_0)*4*d^2).

now, I insert a dielectric (K) between (-d/2<x<d/2), and try to calculate the force now...

it seems like it would be the same but it sounds strange...
If I use the D field, it is not effected by the dielectrics, and thus I can see that the electrical field E is the same as before (D/eps_0) and thus the force is the same...

could it be?
 
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shomey said:
suppose I have a charge q at (x=-d) and a charge q at (x=+d).
the force between them is q^2/(4*pi*(eps_0)*4*d^2).

now, I insert a dielectric (K) between (-d/2<x<d/2), and try to calculate the force now...

it seems like it would be the same but it sounds strange...
If I use the D field, it is not effected by the dielectrics, and thus I can see that the electrical field E is the same as before (D/eps_0) and thus the force is the same...

could it be?


someone? please?
i really need help with this...
 

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