Force between two current-carrying loops

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SUMMARY

The discussion focuses on calculating the magnetic force between two coaxial circular loops, each with a radius of 13.6 cm, separated by 1.20 mm, and carrying a current of 127 A in opposite directions. The user initially attempted to adapt the formula for the force between parallel wires but recognized the need for a different approach due to the unique magnetic field interactions of loops. The solution involves computing the magnetic field produced by one loop and determining the potential energy associated with the magnetic moment of the second loop, ultimately applying the principle of virtual work to find the force exerted.

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  • Understanding of magnetic fields generated by current-carrying loops
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  • Basic calculus for integration and force calculations
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Homework Statement


Consider two circular, parallel, coaxial loops which are almost in contact. They are separated by 1.20mm, have 13.6cm as radius each. Both loops carry a current of I = 127A but in opposite directions. Find the magnetic force that the top loop exerts on the bottom loop.

Homework Equations


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The Attempt at a Solution


I tried to "readapt" the force between two parallel wires, to be able to use it for two loops, in which we would have F = BIl = 2\pi BIr. Then, I used the formula for the field that a loop exerts on its axis, but now I'm doubting if this is true as actually this field is not felt by the other current loop. Now I am stuck on which way to calculate the force that one loop exerts on the other. I was thinking of finding the force exerted on one small piece of the circle dr and then try to integrate in order to find the total force.

Thank you for your time and patience.
 
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Remember magnetic moment? Think of coil 1 as producing a B field along its axis, which you can easily compute. Then, think of coil 2 as having a magnetic moment, and then associate a potential energy U of that moment at the distance between the coils. So U = U(x) where x is the distance between the coils.
Then, appeal to the principle of virtual work which says that force x Δ(distance) = Δ(potential energy).
This problem is a bit advanced for an introductory course but not at all unmanageable (no elliptic integrals, legendre polynomials, etc.).
 
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