Force exerted on a seat on rollercoaster

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SUMMARY

The discussion focuses on calculating the force exerted on a passenger seat at the top of a rollercoaster loop, specifically a loop with a radius of 20m and a hill height of 55m. The correct approach involves using conservation of energy to determine the velocity at the top of the loop, which is calculated to be 32.833 m/s. The net force formula, Fnet = Fg + Fn, is clarified, with Fg representing gravitational force and Fn the normal force. The final answer for the force at the top of the loop is determined to be 1500N, which is not among the provided options.

PREREQUISITES
  • Understanding of centripetal acceleration (ac = v²/r)
  • Knowledge of gravitational force (Fg = mg)
  • Familiarity with conservation of energy principles
  • Ability to apply Newton's second law in circular motion
NEXT STEPS
  • Study the conservation of energy in mechanical systems
  • Learn how to derive velocity using the formula v = √(2gh)
  • Explore the application of Newton's second law in circular motion
  • Investigate the dynamics of forces in rollercoaster design
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in the dynamics of rollercoaster design and forces acting on objects in circular motion.

annamae
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Homework Statement


We have a general rollercoaster design- a hill and a perfect circle loop,
the hill is 55m high and the loop has a radius of 20m. What is the force exerted on the passenger seat at the very top of the loop?
a. 300
b. 500
c. 750
d. 1000
e. 0

Homework Equations


ac=v2/r
Fnet=Fg+Fn+Fp+Ff

The Attempt at a Solution


I found centripetal acceleration to be 15 m/s2
The velocity is 17.32 m/s
Fnet= 60(9.8)+60(15)
But my final answer is 1500N which isn't one of the above choices
So what am i doing wrong?
 
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How did you get that velocity? since v=(2gh)^0.5, you get v=32.833 m/s. Also, what's the mass of the roller-coaster?
 
zush said:
How did you get that velocity? since v=(2gh)^0.5, you get v=32.833 m/s.
No, use conservation of energy between the top of the hill and the top of the loop to find v
Also, what's the mass of the roller-coaster?
Looks like it's 60 kg, from the OP's calc..which was left out of the problem statement.

annamae said:

Homework Statement


We have a general rollercoaster design- a hill and a perfect circle loop,
the hill is 55m high and the loop has a radius of 20m. What is the force exerted on the passenger seat at the very top of the loop?
a. 300
b. 500
c. 750
d. 1000
e. 0

Homework Equations


ac=v2/r
Fnet=Fg+Fn+Fp+Ff

The Attempt at a Solution


I found centripetal acceleration to be 15 m/s2
Yes, how did you arrive at this?
The velocity is 17.32 m/s
yes,how did you arrive at this?
Fnet= 60(9.8)+60(15)
No, Fnet = Fg + Fn, you have written Fnet = Fg + ma
But my final answer is 1500N which isn't one of the above choices
So what am i doing wrong?
Fnet = Fg + Fn = mv2/r, solve for Fn, which is what the problem is asking.
 

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