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Ceshe000
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Homework Statement
A block is placed on a inclined plane. The incline of the plane is 21° .A 24 N force is required to push the block up the incline with constant velocity. The force is applied at an angle of 15° as shown in the picture. The coefficient of kinetic friction (μk) is 0.26. What is the weight of the block? Answer in units of N. The acceleration of gravity is 9.8 m/s/s.
Homework Equations
Force Kinetic Friction = μk * Normal Force
The Attempt at a Solution
The farthest I got in solving the problem was to come up with the force of gravity being 186.5076 N, however I am not entirely sure that this is correct.
To get this I listed the components for each force:
Fn= < 0, Fn >
Fg= < -sin(21)Fg, -cos(21)Fg >
Fpush= < cos(15)Fp, -sin(15)Fp >
Fk= < -μkFn, 0 >
Then is added all the x and y parts together:
Fx:
-sin(21)Fg + cos(15)Fp - μkFn = 0
Fy:
Fn - cos(21)Fg - sin(15)Fp = 0
Then I solved for Fn for each:
Fx:
(cos(15)Fp - sin(21)Fg) / μk = Fn
Fy:
sin(15)Fp + cos(21)Fg = 0
Then I plugged in one Fn for the other:
(cos(15)Fp - sin(21)Fg) / μk = sin(15)Fp + cos(21)Fg
Then I solved for Fg and I am not sure where I messed up doing so...
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