1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Force exerted on the floor by gymnast

  1. Feb 5, 2006 #1
    Can anyone help me with this ?

    Before practicing his routine on the rings, a 74 kg gymnast hangs motionless, with one hand grasping each ring and his feet touching the ground. Both arms make an angle of 26° with the vertical.

    - If the force exerted by the rings on each arm has a magnitude of 290 N, what is the magnitude of the force exerted by the floor on his feet?
  2. jcsd
  3. Feb 5, 2006 #2
    What are you having trouble with? What have you tried so far?
  4. Feb 5, 2006 #3
    Everytime you see a force at a particular angle...you should immediately realize that it can be broken down into components.

    Try thinking about the force in components and see what you come up with.
  5. Feb 5, 2006 #4

    thats just it im not sure how or what to break the components into can anyone help ?
  6. Feb 6, 2006 #5
    Find the guy's weight: W = mg

    Break both forces into F(sub x) and F(sub y): Fcos(26), Fsin(26)

    Find how much of his weight the rings support: W - (F(sub y)rope1 + F(sub y)rope2)

    Remaining weight is supported by floor, thus, F(floor) = (whatever answer you got for the section immediately above)

    Hope that helps

Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?