Force exerted on the floor by gymnast

[Huskies213]

Can anyone help me with this ?

Before practicing his routine on the rings, a 74 kg gymnast hangs motionless, with one hand grasping each ring and his feet touching the ground. Both arms make an angle of 26° with the vertical.


- If the force exerted by the rings on each arm has a magnitude of 290 N, what is the magnitude of the force exerted by the floor on his feet?

 

[d_leet]

What are you having trouble with? What have you tried so far?

 

[Noesis]

Everytime you see a force at a particular angle...you should immediately realize that it can be broken down into components.

Try thinking about the force in components and see what you come up with.

 

[Huskies213]

Re

thats just it I am not sure how or what to break the components into can anyone help ?

 

[FireLight07]

Find the guy's weight: W = mg

Break both forces into F(sub x) and F(sub y): Fcos(26), Fsin(26)

Find how much of his weight the rings support: W - (F(sub y)rope1 + F(sub y)rope2)

Remaining weight is supported by floor, thus, F(floor) = (whatever answer you got for the section immediately above)

Hope that helps

Pat