Force Experienced by Charges between Parallel Plates

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SUMMARY

The force experienced by a charge between two parallel plates is uniform when the plates are large compared to the distance separating them. The electric field (E) between the plates is constant, leading to a force (F) calculated as F = q * E, where q represents the charge. Both positive and negative charges will experience forces proportional to their magnitudes and in opposite directions based on their signs and the direction of the electric field.

PREREQUISITES
  • Understanding of electric fields and forces
  • Familiarity with Coulomb's Law
  • Basic knowledge of charge properties (positive and negative)
  • Concept of uniform electric fields between parallel plates
NEXT STEPS
  • Study the concept of electric field strength in parallel plate capacitors
  • Learn about the implications of charge distribution on electric fields
  • Explore the relationship between electric field and potential difference
  • Investigate the effects of plate size and separation on electric field uniformity
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in understanding electric forces in parallel plate configurations.

Kratos321
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Hello,

Is the force experienced by a charge at any point between two charged parallel plates the same?

Just a preliminary step to my homework question,
Let's say I have two parallel charged plates. (positive on top and negative on bottom with field lines going downwards.).

Would all positive and negative charges experience the same force at any point between the plates?

thanks in advance.
cheers.
 
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When the dimensions of the charged plates are large compared to the distance between the plates then the electric field E that exists between the plates is essentially uniform and of constant value.

The force experienced by some charge q between the plates is then given by q*E. So the magnitude of the force will be proportional to the magnitude of the charge and magnitude of the field, and the direction of the force depends upon the sign of the charge and the direction of the field.
 

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