Force in members of truss; section method

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Homework Help Overview

The discussion revolves around calculating forces in members of a truss using the section method, specifically focusing on members Ffg and Ffh. Participants are attempting to clarify their calculations and assumptions regarding moments and forces.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of moments around different points and question the accuracy of their results. There are attempts to clarify the method used and the assumptions made regarding tension and compression in the members.

Discussion Status

Some participants are providing guidance on the calculation methods and discussing the validity of the results obtained. There is a recognition of differing interpretations of the problem, with some suggesting that the textbook answers may be incorrect.

Contextual Notes

Participants mention the need to consider external reactions and the limitations of the section method, indicating that certain forces may not be relevant once a section is analyzed.

togo
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Homework Statement


295eq8w.jpg


Homework Equations


torque = force x distance

The Attempt at a Solution


35mihxs.jpg


words: hopefully this one is clearer than the last one and someone can follow what I did and figure out where I went wrong. Thanks.

Answer is Ffg=5kn T, Ffh = 20 kn T (only these two members are being questioned)
 
Last edited:
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About what point are you calculating the moments when solving for FH? Your scan is kind of fuzzy.

By the way, I don't get answers that match what you say they're supposed to be.

Also, you might get more responses if you post this type of problem in the engineering section.
 
I see. I calculated for the moment around E. (also double checked the answer in back of book and 5 and 20 are what it says)
 
Last edited:
You left out the moment due to GH.

Try calculating the moments about G instead of E.
 
that sounds like 2 equations with 2 unknowns, I'll work it
 
Me = -28.8 = 1.8FH - 2.4GH

= -16 = FH - 1.333GH

So two unknowns there in calculating for Me. For Mg:

Mg = -(1.8m)(Fh) + (2.4m)(10kN)
= -1.8FH + 24
FH = 13

of course not knowing whether to assume tension or compression, in any case the Mg I calculated is obviously wrong
 
togo said:
Mg = -(1.8m)(Fh) + (2.4m)(10kN)
= -1.8FH + 24
FH = 13

of course not knowing whether to assume tension or compression, in any case the Mg I calculated is obviously wrong
Why is it obviously wrong (other than you didn't specify the units)?
 
Ffh = 20kN (tension) according to the back of the book... (Ffh = Force FH)
 
This is a straightforward problem, so I'm certain the book is wrong. I'll see what the other helpers say.
 
  • #10
an additional question; when using section method you aren't supposed to take into account forces operating on the other side of the section except for the initial calculation of forces holding up the entire truss?
 
  • #11
Right. You start by looking at the structure as a whole to find the external reactions, but once you look at a section, you're only interested in the forces acting on that section.

Another helper got the same results I found. Your result of FFH=13 kN is correct, though the member is under tension, and you should find FFG=3.3 kN, also under tension. The book's answers are wrong.
 
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  • #12
I just wanted to say thanks I'm getting fairly good at these questions now.
 

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