Force needed to raise a backpack

  • Thread starter Thread starter syllll_213
  • Start date Start date
  • Tags Tags
    Force Work
AI Thread Summary
The discussion highlights a misunderstanding regarding the diagram depicting a hiker pulling a backpack with a force at an angle to the vertical, which is labeled incorrectly as a vertical force. It questions the relationship between the force exerted by the hiker on the rope and the tension in the lateral section of the rope. Additionally, it points out the oversight of not considering the contribution from the right half of the rope in the analysis. Clarifying these points is essential for accurately understanding the mechanics involved in raising the backpack. Overall, the conversation emphasizes the importance of correctly interpreting forces and tensions in such scenarios.
syllll_213
Messages
17
Reaction score
1
Homework Statement
The question is asking how the force needed to raise the pack change, but I am unsure if my working and reasoning is right. Particularly, I am unsure if I can assume both the angles (theta) I labelled to be equivalent because I sort of assumed the force pulled by the guy to be equal to the force pulling on the backpack. Some comment on my working would be appreciated thank you TT.
Relevant Equations
F=ma
IMG_40F4ECC612DA-1.jpeg
IMG_FF319B1E65CA-1.jpeg
 
Physics news on Phys.org
The diagram provided seems to have misled you a little. It shows the hiker pulling down at some angle to the vertical but labels a vertical force ##\vec F##.
How does the force with which the hiker pulls on the rope relate to the tension in the lateral section of the rope?

Also, you seem to have forgotten the contribution from the right half of the rope.
 
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
TL;DR Summary: Find Electric field due to charges between 2 parallel infinite planes using Gauss law at any point Here's the diagram. We have a uniform p (rho) density of charges between 2 infinite planes in the cartesian coordinates system. I used a cube of thickness a that spans from z=-a/2 to z=a/2 as a Gaussian surface, each side of the cube has area A. I know that the field depends only on z since there is translational invariance in x and y directions because the planes are...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Back
Top