Force of Particle at x=-0.660 m | Alpha = 1.50 J/m^4

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SUMMARY

The discussion focuses on calculating the force acting on a particle at position x = -0.660 m, given the potential energy function U(x) = 1.50 J/m4 * x4. The force can be determined using the relationship between force and potential energy, specifically F(x) = -dU/dx. By applying this formula, the force at the specified position is calculated as F(-0.660) = -4 * 1.50 * (-0.660)3.

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Homework Statement


A force parallel to the x-axis acts on a particle moving along the x-axis. This force produces a potential energy U(x) given by U(x)= alpha x^4 where alpha=1.50 J/m^4.

What is the force when the particle is at position x = -0.660 m?


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The Attempt at a Solution


I know this has to do with derivaties, a the answer will comes from 4*1.5*some other number cubed. I just don't know what.
 
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How does force relate to the potential U? (This will tell you what to cube)
 

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