Force on 3uC Charge - Solving Coloumb's Law Problem

  • Thread starter Thread starter Ember Cult
  • Start date Start date
  • Tags Tags
    Coloumbs law Law
Click For Summary
SUMMARY

The discussion focuses on calculating the force acting on a 3μC charge using Coulomb's Law. The forces exerted on the charge from two other charges are represented as FA = FAB + FAC, where FAB and FAC are calculated using the formula K*(2*3)/5. Participants emphasize the importance of treating force as a vector, requiring the addition of horizontal and vertical components. Additionally, they highlight that the magnitude of the Coulomb force is inversely proportional to the square of the distance between charges, necessitating corrections in the initial formulas.

PREREQUISITES
  • Coulomb's Law
  • Vector addition of forces
  • Understanding of unit vectors
  • Basic principles of electrostatics
NEXT STEPS
  • Review the derivation of Coulomb's Law and its applications.
  • Practice vector addition in two-dimensional force problems.
  • Explore the concept of unit vectors in electrostatics.
  • Study the effects of multiple charges in both 2D and 3D configurations.
USEFUL FOR

Students studying electrostatics, physics educators, and anyone looking to deepen their understanding of force calculations in electric fields.

Ember Cult
Messages
2
Reaction score
0

Homework Statement


Find force on 3uC charge.
7c3691e89fc776fddf6f46456d2b01b3.png


Homework Equations


3f67479eda67aa1df0b2b44ca10a116d.png


The Attempt at a Solution


Assuming the 3uC charge is at point A and others are at point B and C

FA = FAB + FAC
FAB = K*(2*3)/5
FAC = K*(2*3)/5

 
Physics news on Phys.org
Ember Cult said:

Homework Statement


Find force on 3uC charge.
7c3691e89fc776fddf6f46456d2b01b3.png


Homework Equations


3f67479eda67aa1df0b2b44ca10a116d.png


The Attempt at a Solution


Assuming the 3uC charge is at point A and others are at point B and C

FA = FAB + FAC
FAB = K*(2*3)/5
FAC = K*(2*3)/5

Remember, force is vector. The two forces exerted on the 3uC charge have different directions. Add them by their horizontal and vertical components.
The magnitude of the Coulomb force is inversely proportional to the square of the distance. Correct your formulas.
 
ehild said:
Remember, force is vector. The two forces exerted on the 3uC charge have different directions. Add them by their horizontal and vertical components.
The magnitude of the Coulomb force is inversely proportional to the square of the distance. Correct your formulas.
Your relevant equation should include unit vector of r. Calculating 2 charge particles is not a problem but not in 3D or many particles in 2D.
 

Similar threads

Coloumbs law question (checking answer)
  • · Replies 1 ·
Replies
1
Views
6K
Very hard Coulomb Force with two charges
  • · Replies 4 ·
Replies
4
Views
3K
Use of imaginary charge vs Gauss' law
  • · Replies 12 ·
Replies
12
Views
1K
Understanding Coulomb's Law for Electric Fields and Forces
  • · Replies 7 ·
Replies
7
Views
2K
What Is the Potential of a Spherical Shell with a Grounded Inner Sphere?
  • · Replies 15 ·
Replies
15
Views
5K
How Does Gauss' Law Apply to a Spherical Conducting Shell with a Central Charge?
  • · Replies 5 ·
Replies
5
Views
2K
Electrostatics: Gauss' Law Problem Finding the Flux through a Conducting Spherical Shell
  • · Replies 9 ·
Replies
9
Views
2K
I Thought I Understood Gauss' Law (Sheets)
  • · Replies 26 ·
Replies
26
Views
3K
Point charge with very thin metal sheet along a spherical surface
  • · Replies 21 ·
Replies
21
Views
2K
Electrostatics questions, parallel plates, force, field
  • · Replies 6 ·
Replies
6
Views
3K