Force on a car passenger during acceleration.

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SUMMARY

A passenger in a car accelerating from 0 to 100 km/h (27.77 m/s) in 4.8 seconds experiences a force of 393.52 Newtons. This calculation is derived using Newton's second law, where force (F) equals mass (m) multiplied by acceleration (a). The acceleration is calculated as the change in velocity (Δv) divided by the change in time (ΔT), resulting in an acceleration of 5.78 m/s². The method used is straightforward and confirms the application of fundamental physics principles.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Basic knowledge of kinematics
  • Ability to perform unit conversions (e.g., km/h to m/s)
  • Familiarity with arithmetic operations involving multiplication and division
NEXT STEPS
  • Study detailed applications of Newton's laws in various contexts
  • Explore kinematic equations for different types of motion
  • Learn about forces acting on objects in non-linear acceleration scenarios
  • Investigate real-world examples of acceleration in automotive engineering
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Physics students, automotive engineers, and anyone interested in the dynamics of motion and forces experienced during vehicle acceleration.

Zsmitty3
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1. A Car accelerates from 0-100 km/h (27.77 m/s) in 4.8s. What F (in Newtons) does a passenger of mass 68 kg experience during acceleration



2. I feel like I'm solving this too easily and am missing something



3. F=ma. a= Δv/ΔT.
27.77/4.8= 5.78
F= 68*5.78
F=393.52N ?
 
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Welcome to PF Zsmitty3!

Zsmitty3 said:
1. A Car accelerates from 0-100 km/h (27.77 m/s) in 4.8s. What F (in Newtons) does a passenger of mass 68 kg experience during acceleration



2. I feel like I'm solving this too easily and am missing something



3. F=ma. a= Δv/ΔT.
27.77/4.8= 5.78
F= 68*5.78
F=393.52N ?

I haven't checked your arithmetic, but your method is entirely correct. The problem is not difficult conceptually. It's just a straight application of Newton's second law.
 

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