Force on the car in a collision

Click For Summary
In the discussion about the forces on two colliding cars, both cars A and B have equal mass and are accelerating towards each other with a force of 1000 N each. The application of Newton's third law indicates that during the collision, the forces exerted by each car are equal and opposite, but the total force experienced by either car cannot simply be summed to 2000 N. The conversation highlights the importance of understanding momentum and the nature of forces during a collision, emphasizing that force is not a property of an object but rather an interaction between two objects. The participants clarify that the forces involved depend on the duration of the collision and the velocities of the cars prior to impact, rather than just the forces acting on each car. Overall, the discussion underscores the complexities of analyzing collisions in physics and the need for precise definitions and conditions.
  • #31
Nile Anderson said:
how do we define a force again, I think my error lies there , is it not the change of momentum rather than the momentum
It's neither.
A force is something one body exerts on another. A consequence of a force acting over a period of time can be a change in momentum.
Nile Anderson said:
I am thinking really on a resultant
Sure, but you have to identify the body acted on. If you fix on one of the cars, the other car exerts a force on it during the impact, but it does not exert a force on itself, so the resultant is not zero.
To get a zero resultant here you need to introduce a third object for both cars to act on.
 
Physics news on Phys.org
  • #32
haruspex said:
It's neither.
A force is something one body exerts on another. A consequence of a force acting over a period of time can be a change in momentum.

Sure, but you have to identify the body acted on. If you fix on one of the cars, the other car exerts a force on it during the impact, but it does not exert a force on itself, so the resultant is not zero.
To get a zero resultant here you need to introduce a third object for both cars to act on.
Newton's Second Law ?
 
  • #33
Nile Anderson said:
Newton's Second Law ?
Applied here how, exactly?
 
  • #34
F=mv-mu/t=m(v-u)/t=ma
 
  • #35
Nile Anderson said:
F=mv-mu/t=m(v-u)/t=ma
I asked exactly how you are applying it in the present context. Which body has mass m? What force acting on the body is represented by F? What time period does t stand for?
Anyway, F=m(v-u)/t is not quite right. That will give you the average force over the time interval t. Likewise, your a is the average acceleration.,
 
  • #36
I see , interpretation then
 
  • #37
Nile Anderson said:
I see , interpretation then
No, not interpretation, application. It doesn't mean anything to quote a law in relation to a problem if you cannot state how the entities in the law relate to those in the problem.
 
  • #38
haruspex said:
No, not interpretation, application. It doesn't mean anything to quote a law in relation to a problem if you cannot state how the entities in the law relate to those in the problem.
I say interpretation to say that you are completely right my friend , I have thought about it and that is what I meant you are right , I started with in inaccurate point, trying to defend that point , but deduction can truly get you know where with an incorrect base
 
  • #39
Nile Anderson said:
I say interpretation to say that you are completely right my friend , I have thought about it and that is what I meant you are right , I started with in inaccurate point, trying to defend that point , but deduction can truly get you know where with an incorrect base
OK.
 
  • Like
Likes Nile Anderson

Similar threads

Replies
57
Views
2K
Replies
5
Views
7K
Replies
3
Views
7K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 29 ·
Replies
29
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
10K
Replies
12
Views
1K
  • · Replies 9 ·
Replies
9
Views
4K
Replies
3
Views
1K