Force on rectangular loop by a current in a long straight wire

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SUMMARY

The discussion focuses on calculating the force exerted on a rectangular loop by a current in a long straight wire. The participant initially calculated the magnetic field (B) using the formula Bwire = μo Iwire / 2πd, resulting in a value of 2.56 x 10-3. However, confusion arose regarding the direction of the force on the loop, which was clarified to be downward due to the antiparallel currents in opposite segments of the loop. The consensus is that the force must be calculated for each segment of the loop to accurately determine the net force.

PREREQUISITES
  • Understanding of magnetic fields, specifically Bwire calculation using μo and Iwire.
  • Familiarity with the right-hand rule (RHR) for determining force direction.
  • Knowledge of the concept of antiparallel currents and their effects on magnetic forces.
  • Ability to perform vector calculations for forces on different segments of a loop.
NEXT STEPS
  • Learn about calculating magnetic fields from current-carrying wires in different configurations.
  • Study the principles of forces on current loops in magnetic fields, including segment analysis.
  • Explore the implications of antiparallel currents on magnetic interactions.
  • Investigate advanced applications of the right-hand rule in electromagnetic theory.
USEFUL FOR

Physics students, electrical engineers, and educators looking to deepen their understanding of electromagnetic forces and current interactions in loops.

cherry
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Homework Statement
Consider a long straight wire near a rectangular loop of wire as shown below. The bottom of the rectangle is a distance d = 5.0 cm from the straight wire at its nearest approach, with length L = 16.0 cm and width r = 9.0 cm (so the far edge is at distance d+r from the straight wire).

When I1 = 100.0A and I2 = 40.0A, each in the direction indicated with the arrows, what is the net force on the rectangle of wire?
Relevant Equations
B = μI/2πd
F = Il x B
Hi, I am struggling to get the right answer for this question.
Screenshot 2024-03-17 at 3.41.55 PM.png

My first thought was that I should consider to what direction does each segment of wire have a force towards.
I found the direction to be in the following (see red arrows):
Screenshot 2024-03-17 at 3.42.20 PM.png



My past attempt was:
Floop = IlooplloopBwire
Since Bwire = μo Iwire / 2πd
= 2 * 10-7 * 40 * 0.16 * 100 / 0.05
= 2.56 x 10-3

What I am confused is first of all, is that the force on the rectangular loop is DOWN and not UP (I got this from a multiple choice question that asked for the direction of the force on the rectangular loop).

Am I missing something in this question?
Do I have to solve by calculating the force on each loop segment (ex: solve for top, bottom, left, and right)?

Thank you!
 
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Hi,
You have me wondering what you are calculating, why and especially: how ?

The exercise asks for the force on the loop. So you need B wire, but is that a single value ?

Also, I wonder about the red arrows...
 
BvU said:
Hi,
You have me wondering what you are calculating, why and especially: how ?

The exercise asks for the force on the loop. So you need B wire, but is that a single value ?

Also, I wonder about the red arrows...
My understanding of the question was that since current is a single value, the magnetic field is uniform across the wire and the rectangular loop. Hence, why B wire is also a single value.

I got the direction of force using the RHR.
 
cherry said:
Do I have to solve by calculating the force on each loop segment (ex: solve for top, bottom, left, and right)?
Yes, but you need to get the directions of the forces correctly. Note that segments on opposite sides of the loop carry antiparallel currents. Do antiparallel currents attract or repel?
 
cherry said:
Do I have to solve by calculating the force on each loop segment (ex: solve for top, bottom, left, and right)?
Yes, because this is wrong:
cherry said:
My understanding of the question was that since current is a single value, the magnetic field is uniform across the wire and the rectangular loop. Hence, why B wire is also a single value.
To find the field from the wire at the loop you divided by d, but that only gives the field at the nearest part of the loop. It will be less elsewhere.
 

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