Force on rectangular loop by a current in a long straight wire

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Homework Help Overview

The discussion revolves around the forces acting on a rectangular loop due to a current in a long straight wire. Participants are exploring the relationship between the magnetic field generated by the wire and the resulting forces on the loop's segments.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are considering the direction of forces on each segment of the loop and whether to calculate forces individually for the top, bottom, left, and right segments. Questions arise about the uniformity of the magnetic field and the implications of antiparallel currents on the forces.

Discussion Status

There is an ongoing exploration of the correct approach to calculating the forces on the loop. Some participants are questioning the assumptions regarding the magnetic field's uniformity and the necessity of calculating forces for each segment. Guidance has been offered regarding the need to correctly determine the directions of the forces based on current flow.

Contextual Notes

Participants are grappling with the implications of using a single value for the magnetic field and the effects of distance from the wire on the field strength at different points on the loop.

cherry
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Homework Statement
Consider a long straight wire near a rectangular loop of wire as shown below. The bottom of the rectangle is a distance d = 5.0 cm from the straight wire at its nearest approach, with length L = 16.0 cm and width r = 9.0 cm (so the far edge is at distance d+r from the straight wire).

When I1 = 100.0A and I2 = 40.0A, each in the direction indicated with the arrows, what is the net force on the rectangle of wire?
Relevant Equations
B = μI/2πd
F = Il x B
Hi, I am struggling to get the right answer for this question.
Screenshot 2024-03-17 at 3.41.55 PM.png

My first thought was that I should consider to what direction does each segment of wire have a force towards.
I found the direction to be in the following (see red arrows):
Screenshot 2024-03-17 at 3.42.20 PM.png



My past attempt was:
Floop = IlooplloopBwire
Since Bwire = μo Iwire / 2πd
= 2 * 10-7 * 40 * 0.16 * 100 / 0.05
= 2.56 x 10-3

What I am confused is first of all, is that the force on the rectangular loop is DOWN and not UP (I got this from a multiple choice question that asked for the direction of the force on the rectangular loop).

Am I missing something in this question?
Do I have to solve by calculating the force on each loop segment (ex: solve for top, bottom, left, and right)?

Thank you!
 
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Hi,
You have me wondering what you are calculating, why and especially: how ?

The exercise asks for the force on the loop. So you need B wire, but is that a single value ?

Also, I wonder about the red arrows...
 
BvU said:
Hi,
You have me wondering what you are calculating, why and especially: how ?

The exercise asks for the force on the loop. So you need B wire, but is that a single value ?

Also, I wonder about the red arrows...
My understanding of the question was that since current is a single value, the magnetic field is uniform across the wire and the rectangular loop. Hence, why B wire is also a single value.

I got the direction of force using the RHR.
 
cherry said:
Do I have to solve by calculating the force on each loop segment (ex: solve for top, bottom, left, and right)?
Yes, but you need to get the directions of the forces correctly. Note that segments on opposite sides of the loop carry antiparallel currents. Do antiparallel currents attract or repel?
 
cherry said:
Do I have to solve by calculating the force on each loop segment (ex: solve for top, bottom, left, and right)?
Yes, because this is wrong:
cherry said:
My understanding of the question was that since current is a single value, the magnetic field is uniform across the wire and the rectangular loop. Hence, why B wire is also a single value.
To find the field from the wire at the loop you divided by d, but that only gives the field at the nearest part of the loop. It will be less elsewhere.
 

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