Force on rectangular loop by a current in a long straight wire

AI Thread Summary
The discussion revolves around calculating the force on a rectangular loop due to a current in a long straight wire. The initial approach involved determining the magnetic field and using it to find the force on the loop. However, confusion arises regarding the direction of the force and whether to calculate the force on each segment of the loop. It is clarified that the magnetic field is not uniform across the loop, and the forces on opposite sides of the loop must be considered due to antiparallel currents. Accurate calculations require addressing the magnetic field at different points on the loop rather than assuming a single value.
cherry
Messages
25
Reaction score
6
Homework Statement
Consider a long straight wire near a rectangular loop of wire as shown below. The bottom of the rectangle is a distance d = 5.0 cm from the straight wire at its nearest approach, with length L = 16.0 cm and width r = 9.0 cm (so the far edge is at distance d+r from the straight wire).

When I1 = 100.0A and I2 = 40.0A, each in the direction indicated with the arrows, what is the net force on the rectangle of wire?
Relevant Equations
B = μI/2πd
F = Il x B
Hi, I am struggling to get the right answer for this question.
Screenshot 2024-03-17 at 3.41.55 PM.png

My first thought was that I should consider to what direction does each segment of wire have a force towards.
I found the direction to be in the following (see red arrows):
Screenshot 2024-03-17 at 3.42.20 PM.png



My past attempt was:
Floop = IlooplloopBwire
Since Bwire = μo Iwire / 2πd
= 2 * 10-7 * 40 * 0.16 * 100 / 0.05
= 2.56 x 10-3

What I am confused is first of all, is that the force on the rectangular loop is DOWN and not UP (I got this from a multiple choice question that asked for the direction of the force on the rectangular loop).

Am I missing something in this question?
Do I have to solve by calculating the force on each loop segment (ex: solve for top, bottom, left, and right)?

Thank you!
 
Physics news on Phys.org
Hi,
You have me wondering what you are calculating, why and especially: how ?

The exercise asks for the force on the loop. So you need B wire, but is that a single value ?

Also, I wonder about the red arrows...
 
BvU said:
Hi,
You have me wondering what you are calculating, why and especially: how ?

The exercise asks for the force on the loop. So you need B wire, but is that a single value ?

Also, I wonder about the red arrows...
My understanding of the question was that since current is a single value, the magnetic field is uniform across the wire and the rectangular loop. Hence, why B wire is also a single value.

I got the direction of force using the RHR.
 
cherry said:
Do I have to solve by calculating the force on each loop segment (ex: solve for top, bottom, left, and right)?
Yes, but you need to get the directions of the forces correctly. Note that segments on opposite sides of the loop carry antiparallel currents. Do antiparallel currents attract or repel?
 
cherry said:
Do I have to solve by calculating the force on each loop segment (ex: solve for top, bottom, left, and right)?
Yes, because this is wrong:
cherry said:
My understanding of the question was that since current is a single value, the magnetic field is uniform across the wire and the rectangular loop. Hence, why B wire is also a single value.
To find the field from the wire at the loop you divided by d, but that only gives the field at the nearest part of the loop. It will be less elsewhere.
 
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
TL;DR Summary: Find Electric field due to charges between 2 parallel infinite planes using Gauss law at any point Here's the diagram. We have a uniform p (rho) density of charges between 2 infinite planes in the cartesian coordinates system. I used a cube of thickness a that spans from z=-a/2 to z=a/2 as a Gaussian surface, each side of the cube has area A. I know that the field depends only on z since there is translational invariance in x and y directions because the planes are...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Back
Top