Force Required by Rockets and Angular Acceleration

Click For Summary

Homework Help Overview

The problem involves calculating the force required by rockets to spin a cylindrical satellite at a specified angular velocity. The satellite's mass and radius are provided, along with the desired rotational speed and time to achieve it.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the conversion of angular velocity and the calculation of angular acceleration. There are attempts to apply both translational and rotational dynamics, leading to questions about the appropriate equations and moment of inertia for a cylindrical object.

Discussion Status

Some participants have offered guidance on using the correct rotational equations and moment of inertia. There appears to be ongoing exploration of the calculations, with differing interpretations of the required approach and results.

Contextual Notes

There are indications of confusion regarding the application of translational versus rotational dynamics, as well as the correct moment of inertia for the satellite's geometry. The original poster's assumptions about initial conditions and the setup of the problem are also under scrutiny.

PeachBanana
Messages
189
Reaction score
0

Homework Statement


To get a flat, uniform cylindrical satellite spinning at the correct rate, engineers fire four tangential rockets as shown in the figure. (Picture is attached).

If the satellite has a mass of 4800 kg and a radius of 2.7m , what is the required steady force of each rocket if the satellite is to reach 29 rpm in 6.0 min?

Homework Equations



F = ma
ω final - ω initial / t = α
F/4 = force required by each rocket

The Attempt at a Solution



I converted everything to radians, seconds, etc.

I assumed the initial angular velocity was 0 rad./s.
3.0368 rad./s / 360 s. = 0.00843 rad./s^2

The rockets are being fired tangentially so I then found tangential acceleration.
(2.7 m)(0.00843 rad./s^2) = 0.022761 m/s^2

Then I used F = ma

F = (4800 kg)(0.022761 m/s^2)
F = 109.2528 N

F/4 = 27 N
 

Attachments

  • TheFourRockets.jpg
    TheFourRockets.jpg
    7.5 KB · Views: 500
Physics news on Phys.org
You are mixing translational and rotational equations here. You must stick to rotation. Instead of F = ma, you must use the rotational analog.
 
I think I'm a tad bit closer now.

torque = moment of inertia*angular acceleration

torque = (4800 kg)*(2.7m)^2*(0.00843 rad./s^2)

torque = 294.98256 N * m

Since I want my units to contain only Newtons, shouldn't I divide by the radius?

294.98256 N * m / 2.7 m = 109.2528 N

109.2528 N / 4 = 27 N per rocket

which can't be correct because it's the same as I did before.
 
You're using the wrong moment of inertia; the spacecraft is a cylinder, not a cylindrical shell.
 
tms - Thank you. I obtained the correct answer of about 14 N per rocket.
 

Similar threads

Replies
3
Views
2K
Replies
8
Views
2K
  • · Replies 42 ·
2
Replies
42
Views
6K
Replies
15
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
3K