Force required down an incline.

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SUMMARY

The problem involves calculating the force required to push a 22kg bobsled down a 6-degree incline with a coefficient of kinetic friction of 0.10, aiming for a speed of 60 km/h over a distance of 75 meters. The acceleration needed to achieve this speed is determined to be 1.85 m/s², leading to a required force of 40.7 N. The frictional force opposing the motion is calculated as 21 N. The final answer aligns with the solution provided in the textbook.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Knowledge of kinematic equations (v²=2a(x))
  • Familiarity with friction calculations (Ffr=uFn)
  • Basic trigonometry for incline problems
NEXT STEPS
  • Study the effects of varying coefficients of friction on motion down an incline.
  • Learn about the implications of different incline angles on force calculations.
  • Explore advanced kinematic equations for non-uniform acceleration scenarios.
  • Investigate real-world applications of friction in sports equipment design.
USEFUL FOR

Physics students, mechanical engineers, and anyone interested in understanding dynamics and forces acting on objects on inclines.

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Homework Statement


The co-efficient of kinetic friction for a 22kg bobsled on a track is 0.10. What force is required to push it down a 6 degree incline and achieve a speed of 60km/h at the end of 75m.


Homework Equations


Ffr=uFn
v^2=2a(x)
F=ma



The Attempt at a Solution


(65/3.6)^2=2a(75)
a=2.17ms^-2

F=ma
F=(22)(2.17)
F=47.8

Ffr=uFn=(0.10)(22)(9.8)sin6=21N
But then I am not sure what to do next?
 
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I think I may have been overthinking this problem
The sled is at rest so Ffr=mgcos
So force required is
(60/3.6)^2=2a(75)
a=1.85ms^-2
F=22x1.85=40.7N
Which is the answer in the book.
:mad: Can't believe I worked on this problem for about an hour.
 

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