Force required to accomplish acceleration

In summary, a 200kg motorcycle accelerates uniformly from rest and attains a velocity of 60mph over a distance of 150m. The force required to accomplish this increase in speed is 959N.
  • #1
MMCS
151
0
A 200kg motorcycle accelerates uniformly from rest and attains a velocity of 60mph over a distance of 150m. Determine the force required to accomplish this increase in speed.

Any suggestions?

Thanks
 
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  • #2
Find your list of formulas for accelerated motion. Pick one that doesn't have time in it, since you don't know and don't wish to find time. Or use two of them that do have time, find the time first, then the acceleration.

List of formulas: http://hyperphysics.phy-astr.gsu.edu/hbase/mot.html#motcon
 
  • #3
Thanks for your reply,

I have converted 60mph to 26.8m/s

Then,

Distance/Velocity = time
150/26.82 = 5.59s

Then

Acceleration = change in velocity/time

Acc = 26.82 / 5.59 = 4.79m/s^2

Then

Force = Mass x Acc

4.79 x 200 = 959N

However, i have been given the answer to be 486N
 
  • #4
Delphi51 said:
Find your list of formulas for accelerated motion. Pick one that doesn't have time in it, since you don't know and don't wish to find time. Or use two of them that do have time, find the time first, then the acceleration.

List of formulas: http://hyperphysics.phy-astr.gsu.edu/hbase/mot.html#motcon
(I put that phrase in bold type.)

I have converted 60mph to 26.8m/s

Then,

Distance/Velocity = time
150/26.82 = 5.59s

Then

Acceleration = change in velocity/time

Acc = 26.82 / 5.59 = 4.79m/s^2

Then

Force = Mass x Acc

4.79 x 200 = 959N

However, i have been given the answer to be 486N
The time you got is the time it takes to go 150 meters at a speed of 26.82 m/s. The motorcycle is not traveling that fast until the very end of the 150 m.
 
  • #5
"Distance/Velocity = time" is not an accelerated motion formula. It is a constant speed or zero acceleration formula. Look for one in the list of constant acceleration formulas. It must have an "a" in it for acceleration. You want to find "a" so you can then get the force with F = ma.
 
  • #6
Thanks for your help!
 

1. What is the relationship between force and acceleration?

The relationship between force and acceleration is described by Newton's Second Law of Motion, which states that the force applied to an object is directly proportional to its acceleration. This means that the greater the force applied to an object, the greater its acceleration will be. Additionally, the direction of the force will determine the direction of the acceleration.

2. How is the force required for acceleration calculated?

The force required for acceleration can be calculated using the formula F=ma, where F is the force in Newtons, m is the mass of the object in kilograms, and a is the acceleration in meters per second squared. This formula is derived from Newton's Second Law of Motion.

3. Does the mass of an object affect the force required for acceleration?

Yes, the mass of an object does affect the force required for acceleration. According to Newton's Second Law of Motion, the force required for acceleration is directly proportional to the mass of the object. This means that the greater the mass of the object, the greater the force required to accelerate it at a certain rate.

4. What units are used to measure force and acceleration?

Force is typically measured in Newtons (N), which is equivalent to 1 kg*m/s^2. Acceleration is measured in meters per second squared (m/s^2). These units are derived from the SI (International System of Units) system of measurement and are commonly used in scientific calculations.

5. How does friction affect the force required for acceleration?

Friction is a force that opposes motion and can affect the force required for acceleration. In order to overcome friction and accelerate an object, a greater force must be applied. This is why it is more difficult to push a heavy object across a rough surface, as the friction between the object and the surface requires a larger force to overcome it and accelerate the object.

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