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Force to stabilize a door - torque

  1. Nov 9, 2015 #1
    1. The problem statement, all variables and given/known data
    A 10kg door is hanging on two hinges-the top hinge is 9in from the top of the door, and the bottom hinge is 9in from the bottom of the door. The width of the door is 36in and the height is 86in.

    If the bolt from the bottom hinge is removed, what force would someone have to exert at the door handle (halfway up the height of the door on the far side from the hinge) to stabilize the door?

    2. Relevant equations
    Torque= F r sin theta

    3. The attempt at a solution
    What does it mean by stabilize?
    F(36in)=100N(12)
    Force=33N? maybe?

    What does the problem mean by stabilize? I'm confused
     
  2. jcsd
  3. Nov 9, 2015 #2
    Place in a state of equilibrium.

    Can you explain what you're doing here and where these numbers are coming from?
     
  4. Nov 9, 2015 #3
    Instead of 12 I think I should be using 18.

    So, take the distance from the edge of the door to the handle (36) * F and set it equal to Mg (100N) * (.5*36)
    F(36in)=100N(18in)
    So then my answer would be 50N.
     
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