Force & Viscosity between two parallel plates

[Fleawest]

Homework Statement

A flat circular disc of radius 1.0m is rotated at an angular velocity of 0.65 rad/sec over a fixed flat surface. An oil film separates the disk and the surface. If the viscosity of the oil is 16 times that of water (20 degree C) and the space between the disk and the fixed surface is 0.5mm, what is the torque required to rotate the disk?

Homework Equations

(T/A) = viscosity(dv/dy)

Where,
T= Shear Force
A= Area of the plate
v= velocity
y= gap between plates

The Attempt at a Solution

A= pi(0.5)^2= 0.7854 m^2
v= 0.65 rad/sec
y= 5e-4 m
Viscosity = 16(1.002e-3) = 16.032e-3 N*sec/m^2

How do I turn the rad/sec into shear force and thus torque?

Solving I get T = (0.7854)(16.032e-3)(0.65/5e-4) = 16.37 N*Rad/m

I'm at a loss from here.

 

[Fleawest]

Nevermind, I've got it figured out. I went about it completely wrong. The answer I have now is 2.05 N*m.