What Is the Normal Force Acting On?

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SUMMARY

The discussion clarifies the concept of normal force, specifically in the context of a box resting on a plank, which is in turn on the Earth. It establishes that the normal force exerted by the box on the plank is part of a normal force pair that includes the plank's interaction with the Earth. The conversation emphasizes that for mechanics problems, it is acceptable to simplify the scenario by treating the ground as an idealized immovable surface, thus ignoring complexities related to the mass of the plank and the Earth’s curvature.

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If a box exerts a normal force on the floor, is this strictly on the floor or can we also regard the floor as the Earth?
 
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Think of the Earth as a really huge sphere, which is locally flat. Then imagine a plank of wood somewhere on the sphere (that can be your floor). Finally, you put the box on the plank. There will be a normal force pair between the plank and the Earth, and another normal force pair between the plank and the box. If the plank has mass, then the normal force between the plank and Earth will be slightly more than that between the plank and the box.

Alternatively, you can just take the Earth and the plank to be a single system, and the net force on this system is just the normal force from the box plus the gravitational force from the box.

For mechanics problems, it's often perfectly fine to completely ignore any technicalities about 'floors' and whatnot, and just treat the ground as an idealised immovable surface.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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