Forces and reaction forces generated by a linear actuator

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SUMMARY

The discussion centers on the forces generated by a linear actuator wedged between two solid walls, exerting an outward force of 10N. Participants concluded that in a state of equilibrium, the forces F1 and F2, as well as the reaction forces R1 and R2, must equal 5N each. This is due to the balance of forces, where the total compressive force (20N) must equal the total expansive force (10N) produced by the actuator. Thus, the correct magnitudes of the forces are established as F1 = F2 = R1 = R2 = 5N.

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amrbekhit
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A linear actuator is wedged between two solid walls as shown in the diagram below. The linear actuator is pushing outwards with a force of 10N. What are the magnitudes of the forces labelled in the diagrams?

linearactuatorfreebodydiagram.png


I reckon that F1 = F2 = R1 = R2. However, I'm not sure if F1 = F2 = 5N or 10N. I'm guessing 10N.

Any thoughts?

--Amr
 
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If the system is in equilibrium then all the forces are balanced.

Remember, if R1 = 10N and R2 = 10N that implies that there is 20N compressing the system and we know there is only 10N expanding it.

Jared
 
Hi Jared,

Thanks for your reply. Based on that, if the linear actuator produces a 10N force, F1 = F2 = R1 = R2 = 5N.

Amr
 
I'd agree with that conclusion.

Jared
 

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