1. The problem statement, all variables and given/known data Given F1= 36N[25degrees N of E] and F2= 42N [15 degrees E of S], determine the force F3 that must be added to the sum of F1+F2 to produce a net force of zero. 2. Relevant equations Sine law, a/sina= b/sinb Cosine law: c^2= a^2 + b^2- 2(a)(b) Cos(theta) 3. The attempt at a solution I first went about the question by drawing a vector diagram of all the two know forces, and then I broke down each force into horizontal and vertical components. For F1: F1y= 36N sin25 F1y= 15.2N F1x= 36NCos25 F1x= 32.6N For F2: F2y= 42NCos15 F2y= 40.5N F2x= 42NSin15 F2x= 10.8N Then I added all of the x and y values: ƩFx= 32.6N +10.8N ƩFx= 43.4N ƩFy= 40.5N +15.2N ƩFy=55.7N I then went on to find the resultant vector: F=√43.4N^2 + 55.7N^2 F=70.6N From this point on I have no idea where to go.