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Homework Statement
Given F1= 36N[25degrees N of E] and F2= 42N [15 degrees E of S], determine the force F3 that must be added to the sum of F1+F2 to produce a net force of zero.
Homework Equations
Sine law, a/sina= b/sinb
Cosine law: c^2= a^2 + b^2- 2(a)(b) Cos(theta)
The Attempt at a Solution
I first went about the question by drawing a vector diagram of all the two know forces, and then I broke down each force into horizontal and vertical components.
For F1:
F1y= 36N sin25
F1y= 15.2N
F1x= 36NCos25
F1x= 32.6N
For F2:
F2y= 42NCos15
F2y= 40.5N
F2x= 42NSin15
F2x= 10.8N
Then I added all of the x and y values:
ƩFx= 32.6N +10.8N
ƩFx= 43.4N
ƩFy= 40.5N +15.2N
ƩFy=55.7N
I then went on to find the resultant vector:
F=√43.4N^2 + 55.7N^2
F=70.6N
From this point on I have no idea where to go.