Force Vector Problem: Find Magnitude & Direction of F3

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Homework Help Overview

The problem involves three forces acting on an object, with specific magnitudes and directions given for two of the forces. The objective is to determine the magnitude and direction of a third force such that the vector sum of all three forces equals zero. The context is within the subject area of vector addition in physics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the components of the forces and apply the Pythagorean theorem to find the magnitude of the third force. Some participants question the setup of the equations for the vector sum, suggesting that the equations should reflect the sum of all forces equaling zero. Others express confusion about the angle specification relative to the negative x-axis.

Discussion Status

There is ongoing discussion about the correct approach to summing the forces and the calculations involved. Some participants have provided guidance on the equations that should be used, while others are exploring the reasoning behind the methods taught by their professor. Multiple interpretations of the problem setup are being discussed.

Contextual Notes

Participants note confusion regarding the calculation of force components and the specification of direction. There is an indication that the original poster may be missing some foundational understanding of vector addition principles.

dwagz
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Homework Statement



Three forces are applied to an object, as shown in the figure. Force F1 has a magnitude of 26.8 Newtons (N) and is directed 30.0° to the left of the +y axis. Force F2 has a magnitude of 15.2 N and points along the +x axis. A third force F3 is applied such that the vector sum of the three forces is 0 N. What are (a) the magnitude and (b) direction of this third force? Specify the direction as a positive angle relative to the negative x axis, as shown in the figure.

Picture: http://s236.photobucket.com/albums/ff132/airpenny123/?action=view&current=ch01p_46.gif

Homework Equations



F3X = F1X + F2X
F3Y = F1Y + F2Y

F3= √F3X^2 + F3Y^2


The Attempt at a Solution



F1X = (-26.8N)(.8660)
F1X = -23.21N

F2X = 15.2N

F3X = -23.21N + 15.2N = -8.01N

F1Y = (26.8N)(0.5)
F1Y = 13.4N

F2Y = 0

F3Y = 13.4N + 0 = 13.4N

I found the components of F3X = -8.01 and F3Y = 13.4. When I plug the components into: F3= √F3X^2 + F3Y^2, I get 15.6115 N, which apparently is wrong. I've been on this problem forever and I don't know what I'm doing wrong.

As for this part of the question: "Specify the direction as a positive angle relative to the negative x axis, as shown in the figure." I am completely lost...

Thanks for any help.
 
Last edited:
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Welcome to PF :smile:

I see two problems.

Since the vector sum is zero, the equations should read

F1x + F2x + F3x = 0​

and similarly for the y-components.

Also, calculating the x-component of F1 does not involve cos(30).

As for this part of the question: "Specify the direction as a positive angle relative to the negative x axis, as shown in the figure." I am completely lost...

They just mean the angle from the -x direction.
 
why is that my prof taught us to get first the force sumation in X and in Y and use phytagorean theorem and then get the direction ..
 
Welcome to Physics Forums.
dgiordan said:
why is that my prof taught us to get first the force sumation in X and in Y and use phytagorean theorem and then get the direction ..
That is pretty much how you do this sort of problem, or anything that involves adding vectors. I'm not sure what specifically is confusing you about it?
 

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