Forces and work on an incline help

In summary, during a lab experiment measuring force on an incline, a small concrete block (15.8 kg) was pulled on a wooden ramp and the force increased as the angle of the ramp increased. The coefficient of friction was also examined at different angles, and it was found that at 47 degrees, the coefficient was greater than 1. The force of opposition due to friction and the force normal were taken into consideration, but there may be a missing component as the calculated coefficient is not accurate. The equation used to calculate the net force is F = m*g*sinθ + μ*m*g*cosθ.
  • #1
northern expo
13
0
we are conducting a lab where measurement of force on an incline is necessary. the mass which is pulled is a small concrete block (15.8 kg) on a wooden ramp. as the ramp is increased the force changes (increasing) which is expected. last we need to look at the coefficient of friction at different angles of measure. if we are pulling the block up the ramp at a constant we are finding a force of oppositon due to friction and the force normal. ok, as we are calculating we are finding that the value of this coefficient is increasing and at about 47 degrees of the horizontal plane this value is greater than 1! at the lower angles it is a reasonable value. what are we forgetting? yes we are considering that the force normal is a cosine function of the weight and the force parrallel is the froce we are applying up the ramp. doesn't seem to be correct. what are we missing?
 
Physics news on Phys.org
  • #2
northern expo said:
we are conducting a lab where measurement of force on an incline is necessary. the mass which is pulled is a small concrete block (15.8 kg) on a wooden ramp. as the ramp is increased the force changes (increasing) which is expected. last we need to look at the coefficient of friction at different angles of measure. if we are pulling the block up the ramp at a constant we are finding a force of oppositon due to friction and the force normal. ok, as we are calculating we are finding that the value of this coefficient is increasing and at about 47 degrees of the horizontal plane this value is greater than 1! at the lower angles it is a reasonable value. what are we forgetting? yes we are considering that the force normal is a cosine function of the weight and the force parrallel is the froce we are applying up the ramp. doesn't seem to be correct. what are we missing?

F = m*g*sinθ + μ*m*g*cosθ

I'm just saying, since you didn't mention the component of weight down the incline at sinθ.
 
  • #3
is this F value you are indicating the net F ? We have a measured value for the force up the incline, how is this value

F = m*g*sinθ + μ*m*g*cosθ

included into my equation to find the coefficient value?
 

1. What is an incline in physics?

An incline in physics refers to a sloped surface or ramp. Inclines are commonly used to demonstrate the effects of gravity and forces on objects.

2. What is work in physics?

Work in physics is defined as the product of force and displacement. It is a measure of the energy transferred to an object by a force, causing it to move in the direction of the force.

3. How are forces and work related on an incline?

On an incline, the force of gravity is acting on an object, causing it to slide down the slope. The force of gravity is countered by the normal force of the incline, which is perpendicular to the surface. The work done on the object is the force of gravity multiplied by the distance it travels down the incline.

4. How does friction affect forces and work on an incline?

Friction is a force that opposes motion and acts in the opposite direction of an object's movement. On an incline, friction can reduce the acceleration of an object and affect the work done on the object. More friction will result in less work being done on the object.

5. What is the formula for calculating work on an incline?

The formula for calculating work on an incline is W = mghsinθ, where W is the work done, m is the mass of the object, g is the acceleration due to gravity, h is the height of the incline, and θ is the angle of the incline.

Similar threads

  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
2
Replies
56
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
698
  • Introductory Physics Homework Help
Replies
11
Views
2K
  • Introductory Physics Homework Help
Replies
7
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
399
  • Introductory Physics Homework Help
Replies
2
Views
820
  • Introductory Physics Homework Help
Replies
1
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
297
Back
Top