Forces between parallel currents

Click For Summary
The discussion revolves around the interaction of two parallel electron beams carrying current I and moving in opposite directions. The magnetic force between the beams is calculated using the formula F = (μ0*I1*I2*l)/2πd, leading to F = -(μ0*I^2*l)/2πd when substituting I1 and I2. Participants express uncertainty about calculating the electric force, noting that Coulomb's law applies to both static and moving charges, but the focus should be on the electric field generated by a finite line of charge. The key challenge is to find the ratio of the magnetic to electric force, which is expressed as vε0μ0. The discussion highlights the need for clarity on the electric force in the context of moving charges.
georgia
Messages
8
Reaction score
0

Homework Statement



Two narrow beams of electrons with velocities v and -v are injected into an evacuated chamber along the length l. Each beam moves with constant speed and carries a current I. The tendency for the beams to deflect each other through their mutual interaction is compensated by a magnetic flux density B perpendicular to the plane containing the two electron beams so that they travel in parallel straight lines a distance d apart (d << l). Show that the ratio f of the magnetic to the electric force on each of the beams due to their mutual interaction is vε0μ0

Homework Equations



For two parallel currents I1 and I2 the force on a length l of I2 is:

F= (μ0*I1*I2*l)/2πd

The Attempt at a Solution



Using the above equation and substituting I1 = I and I2 = -I:

F= -(μ0*I^2*l)/2πd

I don't know what to do now, what is the electric force?

All I know is Coloumb's law but I thought that only applied to static charges?
 
Physics news on Phys.org
Coloumb's law applies to all charges, stationary or not. However, in this case you need to consider the electric field of a finite line of charge. Have you met this before?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 24 ·
Replies
24
Views
2K
  • · Replies 29 ·
Replies
29
Views
2K
  • · Replies 6 ·
Replies
6
Views
947
  • · Replies 9 ·
Replies
9
Views
2K
Replies
7
Views
1K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
1
Views
1K
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K