Find the force between two wires

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Homework Help Overview

The discussion revolves around calculating the force between two perpendicular current-carrying wires. The original poster presents a specific scenario involving two wires, each carrying a current of 2 A and separated by a distance of 5 meters, and attempts to apply a formula for the force between them.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between the currents and the magnetic fields generated by the wires. There are discussions about the directions of the currents and magnetic fields, and whether the original poster's approach to calculating the force is appropriate given the perpendicular orientation of the wires.

Discussion Status

Some participants have offered guidance on understanding the vector relationships involved in the problem, particularly regarding the Lorentz Force and the implications of using the force formula for parallel versus perpendicular wires. There is an ongoing exploration of the concepts without a clear consensus on the resolution of the problem.

Contextual Notes

Participants note that the original poster may be working with problems outside of their textbook, leading to uncertainty about which concepts and methods are most applicable. There is also mention of the Right Hand Rule and its relevance to the problem at hand.

zade70
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Homework Statement


Two rectilinear wires with length 100 m have the intensity 2 A. The wires in are perpendicular directions with distance 5 meters from each-other. Find the force they interact.

Homework Equations


F=(I1*I2*μ0*l)/(2*pi*d)

The Attempt at a Solution


F=(2*2*4*pi*10^-7*1)/(2*3.14*5)=1.6*10^-7
The solution in my book is 0 N.
 
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Check the direction of the magnetic fields and the direction of the currents...
 
BvU said:
Check the direction of the magnetic fields and the direction of the currents...
I think the currents are perpendicular with each other and so are the vectors of magnetic induction.
 
zade70 said:
I think the currents are perpendicular with each other and so are the vectors of magnetic induction.
Yep. So what force would that generate?
 
berkeman said:
Yep. So what force would that generate?
I can't find an argument for that.
 
zade70 said:
I can't find an argument for that.
Okay, so I'm getting the impression that you have not been exposed to the vector relationship between the current in a wire and the B-field that circulates around it, is that right? Also, have you learned how to calculate the vector Lorentz Force?
 
berkeman said:
Okay, so I'm getting the impression that you have not been exposed to the vector relationship between the current in a wire and the B-field that circulates around it, is that right? Also, have you learned how to calculate the vector Lorentz Force?
I don't know what the Lorentz Force is. I know that F=B(induction)*l(length)*I(intensity)*sin alpha. I also know that the force is perpendicular with current and induction
 
zade70 said:
I don't know what the Lorentz Force is. I know that F=B(induction)*l(length)*I(intensity)*sin alpha
Do they have any diagrams in your textbook that show a current carrying wire and the B-field circling around the wire? Do they discuss and show the "Right Hand Rule" for the direction of the B-field? I'm just trying to get a feel for how the book wants you to know how to answer this question...
 
berkeman said:
Do they have any diagrams in your textbook that show a current carrying wire and the B-field circling around the wire? Do they discuss and show the "Right Hand Rule" for the direction of the B-field? I'm just trying to get a feel for how the book wants you to know how to answer this question...
Yes. I have learned the Right Hand Rule. Actually I am doing some problems that are not from the book I'm studying and I don't know which is appropriate for me to do with the knowledge I have so far.
 
  • #10
zade70 said:
Yes. I have learned the Right Hand Rule. Actually I am doing some problems that are not from the book I'm studying and I don't know which is appropriate for me to do with the knowledge I have so far.
Ah, that might explain it. Yeah, just using the force formula for parallel wires will not work for perpendicular wires.

The B-field for a current carrying wire looks like this:

http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/magcur.html#c1
magcur.gif


And the Lorentz Force is written as the cross product of two vectors: F = qv X B Where F is the force vector, v is the velocity vector of a charge, and B is the magnetic field vector. Vectors have both a Magnitude and a Direction.

The vector cross product can be simplified if you are not familiar with it, so the Lorentz force can be re-written as magnitudes only F = qvB sin(θ), where θ is the angle between the velocity vector v and the magnetic field vector B. So the result of the cross product is maximized when v and B are in the same (or opposite) direction, and it is zero when they are perpendicular.

Does that help some? You can do more reading about this at Hyperphysics or Wikipedia. :smile:

Edit -- not sure why the image is not displaying correctly, but you can click on the link to see it.
 
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