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## Homework Statement

A charge of [tex]8\times 10^{-5}[/tex]C is placed in an electric field [tex](3000\b{i}-600\b{j})[/tex]N/C. What are the (a) magnitude and (b) direction (relative to the positive direction of the [tex]x[/tex]-axis) of the electrostatic force?

## Homework Equations

[tex]F=Eq_0[/tex]

## The Attempt at a Solution

(a) [tex]F=(0.24\b{i}-0.048\b{j}) \implies |F| = 0.245[/tex]N

(b) How is direction determined? I understand it's positive charge thus the field is always pointing away from the charge. By finding angle, [tex]\theta = \tan ^{-1}\left(-0.048/0.240) = -11.3^o[/tex], but what does the force direction actually point in? Away from origin, towards origin? The angle I found, I cannot relate to theory. Can someone explain the direction.

Thanks in advance.