Forces On a Moving Train Traveling Around a Curve

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SUMMARY

The discussion focuses on calculating the forces acting on a train traveling around a curve at a constant speed of 200 mph, with specific parameters including a weight of 101,605 kg and a radius of 500 m. Key forces to analyze include centripetal force, gravitational force, and the resultant forces acting on the train due to its motion. The participants clarify that while the speed is constant, the direction of the train's velocity changes, necessitating a centripetal force for circular motion. The importance of the banking angle and the center of mass in determining safe speeds on curves is also highlighted.

PREREQUISITES
  • Understanding of Newton's laws of motion, specifically F = MA.
  • Knowledge of centripetal force and its role in circular motion.
  • Familiarity with gravitational force calculations.
  • Basic principles of physics related to motion and forces.
NEXT STEPS
  • Calculate centripetal force for a train moving at 200 mph around a 500 m radius.
  • Explore the implications of banking angles on train safety and speed limits.
  • Investigate the effects of mass distribution on the center of mass in train design.
  • Learn about the dynamics of circular motion in high-speed rail systems.
USEFUL FOR

Physics students, engineers in transportation design, and safety analysts in railway systems will benefit from this discussion, particularly those interested in the dynamics of high-speed trains navigating curves.

tomtomtom1
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TL;DR
Forces Involved Of A Moving Train Travelling Around A Curve
Hello all

I am trying to work out the forces involved of a moving train around a curve traveling at a constant speed.

I have the following:-

Trains.JPG


The image on the left is a cross section of a train traveling around a curve, you can think of the train moving away from you.

The image on the right in the same train but in plane view but illustrates the radius.

I am trying to work out the Forces F1, F2 and F3.

I know the following:-

- Speed = 200mph

- Weight = 101605kg

- Radius = 500m

- Gravity = 9.81m/s^2

- Distance between Rails = 1.2m

- Height Difference between Rail A and Rail B = 0.090m

- Angle = 4.30 deg

The first thing that I tried to do was to convert the train weight of 101605 kg into a Mass by dividing by 9.81 m/s^2, however I ended up with some strange units:-

101605kg / 9.81m/s^2 = 10357.28848 (kg s^2)/m - ??

The reason why I wanted to find the Mass was because I wanted to use the F = MA equation to work out Force in Newtons.

Because I didn't get far with this I tried to convert the speed of the train which is 200mph into an acceleration but since the train is traveling around the curve at a constant speed of 200mph there is no acceleration which I am struggling to come to terms with.

Can I ask how would the Forces F1 F2 and F3 be worked out?

Can anyone point me in the right direction?

Thank you.
 
Last edited by a moderator:
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tomtomtom1 said:
Weight = 101605 kg
Do you mean mass = 101605 kg ? The kilogram is a unit of mass.

tomtomtom1 said:
constant speed of 200mph there is no acceleration
There is: the velocity of the train changes. Not in magnitude but in direction.

For a circular motion a centripetal force is needed. Can you find out how big it has to be in this case ?

[edit]
200 mph is a disaster speed for a curve radius of 500 m
 
BvU said:
[edit]
200 mph is a disaster speed for a curve radius of 500 m
It's not entirely unreasonable if the train is a roller coaster...
 
200 mph, 500 m -- not a roller coaster
 
I know, I was being a bit facetious (though the fastest roller coaster is 150mph, so that's not that far off). That would be just about a 2G curve though, so it would be pretty ridiculous (and it would require 60 degree banking).

EDIT: Maybe it's 5km? That bank angle from OP's diagram is still not quite enough even in that case, but it at least seems to kind of work out as reasonable...
 
I don't see the position of the center of mass of the car noted anywhere. That will of course determine the actual disaster speed.
 
F3 would be the weight multiplied by the cosine of the incline.
 

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