- #1

SevenToFive

- 56

- 3

The cart is steel wheels on a steel rail so I figured 0.5 coefficient of friction.

The total tractive effort (TTE) = Rolling Resistance(RR) + Grade Force(GF) + Force for Accelerate(FA)

For RR=weight * surface friction = 20,000lbs * 0.5

RR=10000lbs

GF= Weight * Sin(Degrees) = 20000lbs * Sin(0)

GF=0

FA = Weight * max speed(ft/s) /(32.2ft/s^2 * Time in Seconds)

Max speed would be radius * rpm * 0.10472 = 5" * 44rpm * 0.10472

Max speed (ft/s) = 1.92ft/s

20000lbs * 1.92ft/s /(32.2ft/x^2 * 1sec)

Force Acceleration (FA) = 1193lbs

TTE=10000lbs+0+1193lbs

TTE=11193lbs

Wheel torque = TTE * Wheel Radius

Wheel torque = 11193lbs * 5inches

Wheel torque needed to move the 10 ton cart is 15,965in-lbs.

If I am close I can size the gearbox and then only have to worry about the operating temperature that the gearbox will be in since it is being used to move a cart in and out of a heat treating furnace.

Thanks to all who reply.