(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two forces act on a 4.00 kg mass which is sitting at rest on a horizontal frictionless surface. One force is 6.50 N directed 55° West of South, the other is 7.00 N directed 25° North of West. What acceleration does the mass receive?

2. Relevant equations

sin = o/h

cos = a/h

tan = o/a

a = F/m

3. The attempt at a solution

I drew forces (not accurately) on paint (attachment) to help me solve this question then did the following calculations:

Fapx1

sin = o/h sin35° = o/6.5N o = 3.7N

Fapx2

sin = o/h sin25° = o/7N o = 3N [N]

Fapx = Fapx1 + Fapx2

Fapx = 3.7N - 3N

Fapx = 0.7N

Fapy1

cos = a/h cos35° = a/6.5N a = 5.3N [W]

Fapy2

cos = a/h cos25° = a/7N a = 6.3N [W]

Fapy = Fapy1 + Fapy2

Fapy = 5.3N + 6.3N

Fapy = 11.6N

************************************************

tan = o/a tan = 11.6/0.7 tan = 86.5°

sin = o/h sin86.5° = 11.6/h h = 11.622N

************************************************

a = F/m a = 11.622N/4.00kg a = 2.9 m/s^2

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I was wondering if I did the question right. Did I get the right answer?

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: Forces with angles, Find the acceleration

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