Forgotten Units: kg, m/s^2, cm^3, mL Explained

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SUMMARY

The discussion centers on the conversion and understanding of various physical units, specifically focusing on the relationship between kilograms (kg), meters per second squared (m/s²), and Newtons (N), as well as the equivalence of cubic centimeters (cm³) and milliliters (mL). Participants confirm that 1 cm³ equals 1 mL and clarify that (kg)(m/s²) equals Newtons. The conversation also addresses unit conversions in calculations involving pressure and volume, emphasizing the need to convert all units to a consistent type for accurate results.

PREREQUISITES
  • Understanding of basic physics concepts, including force and pressure.
  • Familiarity with unit conversions, particularly between metric units.
  • Knowledge of the Ideal Gas Law and related constants.
  • Basic algebra for manipulating equations and units.
NEXT STEPS
  • Research the Ideal Gas Law and its applications in real-world scenarios.
  • Learn about unit conversion techniques, focusing on pressure units like atm and Pascal.
  • Study the various forms of the gas constant, particularly 8.314 J * mol^-1 * K^-1.
  • Explore resources for unit conversion and physical constants, such as online calculators or educational websites.
USEFUL FOR

Students in physics or chemistry, engineers working with fluid dynamics, and anyone needing to understand unit conversions in scientific calculations.

nemzy
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What does (kg)(m/s^2) = what unit?

also does 1 cm^3= 1 mL?

i forgot all these units stuff its really bugging up my mind
 
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(kg)(m/s^2) = Newton

1 cm^3= 1 mL Yes
 
ok, I am confused, I've been stuck on this problem for about an hour

So far i got this in my calculations:

(5.316 L*atm) / ( (211.68 kg*m/s^2)+(.0073m^2*atm))

the answer is suppose to be in meters, and from these units i have no idea how it is possible..anyone have any ideas?
 
Show your work, by the way, L is liters right?
 
oh yeah and 1 more question, if u add units, then what happens?

like for example, if u have 8 atm + 3 liters, will it become 11 (atm+liters)?
 
k here is my work:

the equation is this:

h=n*R*T/(m*g+Po*A)

n= 1.85 moles
R=gas constant
T= 350 K
A= .00730 m^2
m= 21.6 kg

and Po is atmospheric pressure (1 atm or 1.0135e5 kPa)
 
Absolutely Not!
 
I don't believe you can do that, look up atm basic units, i mean Newton is kg*m/s^2, what is atm equal to? and use the relation above cm^3 = mL, and see if you can follow from that. This problems can be solved by converting to the same types of units, and simple elimination of analogous units.
 
that last post was directed at the previous post...about adding units
 
  • #10
a Pascal is N/m^2, use that. Also 1 atm = 101325 pascal.
 
  • #11
ok, so i ended up with this:

5.315975 L*atm / (211.68 N +739.6725 m^2*Pa)

but i am stuck here, how can i cancel out further units? since the bottom is addition, i have no idea what to do from here...am i still allowed to convert the m^2 to liters and cance it out with the top, as well as the Pa with the atm on top?
 
  • #12
well, a pascal times m^2 is just Newtons!

so you have all Newtons on the bottom...then instead of using that gas constant...use the one that is J * mol^-1 * K^-1

then you have J / N...which is meters (change them to their base forms if you want to double check it :) )
 
  • #13
nicely done :smile:
 
  • #14
gas constant:

8.314 J * mol^-1 * K^-1

instead of

8.2057 L * atm * mol^-1 * K^-1

there are a few other forms of the gas constant too, but these are the most commonly used ones.
 
  • #15
thx! i finally got the right answer..this units are really bugging

does anyone know a website that has all these info?
 
  • #16
It should be on your textbook, if not try google.
 

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