The discussion revolves around finding the equivalent capacitance using delta-star conversion in capacitors. Participants are exploring the application of delta-star transformations, which are typically associated with resistances, to capacitive circuits.
The discussion is ongoing, with participants sharing different approaches and questioning the assumptions behind the transformations. Some guidance has been offered regarding the algebra involved in the conversion process, but no consensus has been reached on a definitive method.
There is mention of using specific values for frequency to simplify calculations, and participants are considering the implications of treating capacitors similarly to resistors in their transformations.
Curious3141 said:The slow way to do it is from first principles.
The quick way is to use the AC impedance of a capacitor, which is ##\displaystyle \frac{1}{j\omega C}##, which can be treated like a resistance, then apply the delta-star conversion formula to it and see what you end up with. Remember to convert the final impedance you get back to a capacitance by reversing the formula.
Looks like it's just a bit of algebra. Logically, you know that ω should ultimately play no role in the capacitance values you obtain, so it should cancel out along the way. Might as well just eliminate it from the start (or choose a convenient working frequency such as ω = 1). That may make things less cluttered looking.Greg Arnald said:there for if capacitors.. 1/ωCa=(1/ωC2*1/ωC3)/(1/ωC1+1/ωC2+1/ωC3). (??)
How do I convert this back to capacitance so I just have Ca=...?