I Formula for maximum angular frequency and velocity

AI Thread Summary
The formula Vmax = Wmax x L describes the maximum speed of a pendulum bob, where Wmax represents the maximum angular speed. The equation can be interpreted as Vmax = ωmax x L, with ωmax being the maximum angular speed and L the length of the pendulum. The second equation, Wmax = Wθmax, involves two different definitions of angular speed, with ωmax indicating the rotation rate at the bottom of the swing and ω representing the angular frequency of oscillations. The discussion highlights the confusion arising from the notation and suggests a clearer representation of the relationship between angular speed and deflection angle. Understanding these formulas is essential for analyzing pendulum motion effectively.
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I can't seem to find it anywhere
What does this formula mean ? I can't find it anywhere. Vmax=Wmax x L. And Wmax=Wθmax. It came up in the pendulum chapter. L is string length.
 
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I can imagine that Vmax=Wmax x L is actually ##V_{\text{max}}=\omega_{\text{max}}L## where
##V_{\text{max}}=~## maximum speed of the pendulum bob
##\omega_{\text{max}}=~## maximum angular speed of the pendulum relative to the point of support
##L=~## the length of the pendulum.

I cannot imagine what Wmax=Wθmax could be.
 
MenchiKatsu said:
And Wmax=Wθmax. It came up in the pendulum chapter. L is string length.
$$\omega_\text{max} = \omega \theta_\text{max}$$I will make a guess at this one. The notation is confusing because there are two different omegas (##\omega##) being considered here.

On the left hand side of the equality we have ##\omega_\text{max}## which is the rotation rate (in radians per unit of time) for the pendulum at the bottom of its swing.

On the right hand side of the equality we have ##\omega## which is the angular frequency of the oscillations of the pendulum.

Finally we have ##\theta_\text{max}## which is the maximum deflection angle of the pendulum from the vertical.

For instance...

If we have a one meter pendulum under earth gravity, its period is about two seconds. This is an angular frequency (##\omega##) of about ##2 \pi## radians per ##2## seconds. Or about one radian per second.

If this pendulum is launched from rest at a deflection angle (##\theta_\text{max}##) of ##0.1## radians from the vertical, the equation asserts that the rotation rate (##\omega_\text{max}##) of the pendulum at the bottom of its arc will be ##0.1## radians per second.
 
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jbriggs444 said:
I will make a guess at this one. The notation is confusing because there are two different omegas (ω) being considered here.
I agree. It should be something like $$\omega_{\text{max}}=\theta_{\text{max}}\sqrt{\frac{g}{L}}$$ where ##\omega## is a reserved symbol for the angular speed of the pendulum bob.
 
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