Formulating an Eigenvector Equation

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SUMMARY

The discussion focuses on solving the eigenvector equation for a double pendulum system represented by the matrices K and M. The correct approach to find the normal mode frequencies involves calculating the determinant of the matrix equation K - ω²M and setting it to zero. The participants clarify that rearranging the equation to M⁻¹Kα = ω²α is unnecessary and may lead to errors. Instead, the determinant method provides a straightforward solution for determining the eigenvalues.

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  • Understanding of eigenvalue problems in linear algebra
  • Familiarity with matrix operations, specifically determinants
  • Knowledge of normal mode analysis in mechanical systems
  • Experience with double pendulum dynamics
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Hello. I am working on a project with a double pendulum and I am currently looking for the normal mode frequencies. I don't think that's too important to answer my question, but in the derivation I hit a point that look like this:(K-M\omega^{2})\alpha=0. Here, K and M are 2x2 square matrices. I want to solve for the eigenvalue here, but this doesn't follow the form that I normally have with eigenvector equations. If I rearrange this, I get K\alpha=M\omega^{2}\alpha which has a matrix on each side. Naturally I thought to multiply by the inverse of M on both sides to get M^{-1}K\alpha=\omega^{2}\alpha. However, this didn't give the correct result. Why not? How should it be done?
 
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You must have K or M wrong, or both.
Check again, or submit the original problem and your approach here.
 
Finding the eigenvalues of ##M^{-1}K## works. You must have made a mistake somewhere.

But you don't need to do that. Just find the determinant of ##K-\omega^2M##, and find the values of ##\omega## that make it zero.

$$\left|\begin{matrix} k_{11}-\omega^2m_{11} & k_{12}-\omega^2m_{12} \\
k_{21}-\omega^2m_{21} & k_{22}-\omega^2m_{22} \end{matrix} \right| = (k_{11}-\omega^2m_{11})(k_{22}-\omega^2m_{22}) - (k_{12}-\omega^2m_{12})(k_{21}-\omega^2m_{21}) $$
 

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