Foundation System Homework: Determine Load Capacity/Area of Steel

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SUMMARY

The discussion centers on determining the load capacity of a foundation wall system with specific measurements and material properties. The wall is designed with a compressive strength of 3,000 psi and a yield strength of 40,000 psi, with an allowable soil bearing capacity of 4,000 psf. The wall loads are defined such that the live load is three times the dead load, and the calculations provided include maximum unfactored live and dead loads of 11,385 lbs/ft and 3,795 lbs/ft, respectively. The area of longitudinal steel required is 1.728 square inches, utilizing six #5 rebar bars for reinforcement.

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Homework Statement



Again, I have a question where I have not idea what I did wrong... Please give suggestions! Thanks. Work is shown on attachment.



You have a foundation wall system in the field that you were asked to determine the load capacity of per lineal foot. The wall has the following measurements and specifications:


Specifications:

f c' = 3,000 psi f y = 40,000 psi Allowable soil bearing capacity = 4,000 psf

Wall loads: live = three times the dead load per foot
dead = one third the live load per foot

Cover for footer steel = 3”

#4 rebar at 9” center to center for main steel
___ - #5 rebar for temperature steel

Wall load includes the weight of the wall however not the weight of the footer.

Wall thickness = 8” Footer depth: h = 16” Footer width: w = 4’- 6”

Note: Perform and show all code check considerations.

Maximum unfactored live load the wall footer can safely carry: __11385______ #/’

Maximum unfactored dead load the wall footer can safely carry: ____3795____ #/’

Area of longitudinal steel: __1.728_____ sq in __6_____ - # 5 bars



Homework Equations





The Attempt at a Solution



View attachment question3.pdf
 
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Not my field but..

I notice the question says "4000 psf". I might be wrong but your answer sheet appears to say "T = 4000 psi" ?
 
CWatters said:
Not my field but..

I notice the question says "4000 psf". I might be wrong but your answer sheet appears to say "T = 4000 psi" ?

You are correct. I miss labeled it. This would not affect the answers
 

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