Fourier Series - Asymmetric Square Wave

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SUMMARY

The discussion focuses on the computation of Fourier coefficients for an asymmetric square wave using the Fourier series, as presented in Alan Oppenheim's Signals and Systems course. The Fourier coefficient is derived using the equation ak = (1/T0) [∫ (-1)ejkω0t + ∫ (1)ejkω0t]. Participants clarify that the constants ±1 do not require complex integration techniques such as u-substitution or integration by parts. The final expression for the Fourier coefficient is ak = (1/jkπ)(1 - (-1)k), and users are encouraged to compute initial values to understand the behavior of the (-1)k term.

PREREQUISITES
  • Understanding of Fourier series and periodic signals
  • Familiarity with complex exponentials and Euler's formula
  • Basic knowledge of integration techniques, including integration by parts
  • Concept of angular frequency and its relationship with the period
NEXT STEPS
  • Review the derivation of Fourier series for various waveforms
  • Practice integration techniques, specifically integration by parts and u-substitution
  • Explore the implications of the (-1)k term in Fourier coefficients
  • Study the relationship between T0 and ω0 in Fourier analysis
USEFUL FOR

Students and professionals in electrical engineering, particularly those studying signals and systems, as well as anyone interested in mastering Fourier analysis techniques.

DmytriE
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Good morning everyone,

I am taking a signals and systems course where we are now studying the Fourier series. I understand that this is for signals that are periodic. But I get hung up when determining the Fourier coefficients. In the video by Alan Oppenheim, he derives the equation for the Fourier series. Below is the analysis equation.

a_{k} = \frac{1}{T_{0}} ∫ x(t)*e^{jk\omega_{0}t}

He goes through an example using an asymmetric square wave with an amplitude of 1. I understand the bounds that he chooses (-T_0/2, 0) and (0, T_0/2).

This leads to a Fourier coefficient equation of the following:
a_{k} = \frac{1}{T_{0}} [∫ (-1)*e^{jk\omega_{0}t} + ∫ (1)*e^{jk\omega_{0}t}]

To compute the general equation for a_k should I treat the ±1 as a function and use u-substitution / integration by parts? If so, can someone at least show the first step or 2? I haven't done I.B.P. or U-substitution in some time. If I can treat the x(t) as a constant then how can I integrate to get the answer below?

General equation: a_k = \frac{1}{jkπ} (1 - (-1^{k}))

This example is from M.I.T. Open Courseware Alan V. Oppenheim Signals and Systems course Lecture 7 approximately 20 minutes into the video.
 
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DmytriE said:
This leads to a Fourier coefficient equation of the following:
a_{k} = \frac{1}{T_{0}} [∫ (-1)*e^{jk\omega_{0}t} + ∫ (1)*e^{jk\omega_{0}t}]
To compute the general equation for a_k should I treat the ±1 as a function and use u-substitution / integration by parts?[/itex]
You don't need to do all that. "1" and "-1" are just constants. If you are studying this, you should know ##\int e^{at}dt##, and that formula works when ##a## is a complex number as well as when ##a## is real.

You should also know ##e^{j\omega t} = \cos \omega t + j \sin \omega t##.

You also have an equation connecting ##T_0## and ##\omega_0##, which is why they both disappeared in the final equation for ##a_k## (and that's also where the ##\pi## came from).

If you are confused by the ##(-1)^k## part, just work out the first few values of ##a_1##, ##a_2##, etc and see what happens.
 
AlephZero said:
If you are confused by the ##(-1)^k## part, just work out the first few values of ##a_1##, ##a_2##, etc and see what happens.

This is precisely what I am confused about. Is there a rule that applies to the (-1)^k or do I have to input a couple numbers for a_k?
 

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