Fourier Series at Discontinuities

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SUMMARY

The Fourier Series converges at a finite discontinuity of a periodic function to the average of the limiting values from either side of the discontinuity. Specifically, at a point x1 where the function has values y1 and y2, the series converges to 1/2*(y1 + y2). In the discussed case, with y1 equal to 2 and y2 equal to 5, the Fourier Series converges to 3.5, not to the difference between the two values. This highlights the importance of understanding the convergence behavior of Fourier Series at discontinuities.

PREREQUISITES
  • Understanding of Fourier Series and their properties
  • Knowledge of periodic functions and discontinuities
  • Familiarity with limits and convergence concepts
  • Basic mathematical skills in algebra and calculus
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  • Study the convergence properties of Fourier Series in detail
  • Explore the implications of discontinuities in periodic functions
  • Learn about Gibbs phenomenon in Fourier Series
  • Investigate applications of Fourier Series in signal processing
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Mathematicians, engineers, and students studying signal processing or harmonic analysis who seek to understand the behavior of Fourier Series at points of discontinuity.

Hermes10
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Dear all,

I am wondering why the Fourier Series converges at a finite discontinuity of a periodic function at 1/2*(y1+y2) at the point f(x1), where x1 is the point at which the discontinuity occurs and y1 is the limiting value for the function when we approach x=x1 from one side and y2 is the limiting value when we approach x=x1 from the other side?

Say, in a particular case y2 is 5 and y1 is 2, shouldn't the Fourier series converge to 1/2*(5-2)? I would have though that the Fourier series just converges at the midpoint between y1 and y2 on the graph that is if you draw the function I would have draw the value for x1 at which the discontinuity occurs to be in the middle of the two limiting values. Is that correct?

All the
Hermes10
 
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Your idea is correct, except for an error (typo?) y2=5 and y1=2 gives 1/2(5+2) as the midpoint.
 

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