Fourier transform and steady state solution?

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The discussion centers on the relationship between Fourier transforms and steady state solutions. It is noted that the Fourier transform can identify the frequency components of a stationary signal, such as f(t), which consists of multiple cosine functions. In contrast, the transient signal g(t) has varying frequencies over time but yields a Fourier transform similar to that of f(t). This similarity highlights the limitation of Fourier transforms in analyzing non-stationary signals, suggesting the need for alternative methods like wavelet transforms. The conversation emphasizes the distinction between stationary and transient signals in the context of Fourier analysis.
hanson
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Hi all!
I am asking about a question about Fourier transform.
I can only roughly remember things about Fourier transform.
I am told that Fourier transform gives the steady state solution, is it?
I can hardly relate these two concepts.
Can someone try to explain?
Many thanks.
 
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May be http://users.rowan.edu/~polikar/WAVELETS/WTpart1.html" might give a clue in understanding.

Let say that we have a signal
f(t) = cos(20\pi t) + cos(50\pi t) + cos(100\pi t) + cos(200\pi t)
which is a stationary signal (steady state I presume). The Fourier transform of this signal will identify that this signal has frequencies of 10, 25, 50, and 100 Hz at any given time instant.
Next consider another signal of period 1s,

g(t)=\left\{\begin{array}{cc}cos(200\pi t),&amp;\mbox{ if }<br /> 0\leq t &lt; 0.3 \\<br /> cos(100\pi t), &amp; \mbox{ if } 0.3 \leq t &lt; 0.6 \\<br /> cos(50\pi t), &amp; \mbox{ if } 0.6 \leq t &lt; 0.8 \\<br /> cos(20\pi t), &amp; \mbox{ if } 0.8 \leq t &lt; 1 <br /> \end{array}\right

Signal g(t) is a transient signal. But the Fourier transforms of g(t) and f(t) are almost identical. So given some coeffients, the Fourier transform will identify the signal as f(t) the stationary signal.
To analyse the second signal we use other transform e.g. wavelet transform.

What am I writing here?
 
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