Fourier Transform of Trigonometric Polynomials | Learn How It Works

Click For Summary
The discussion centers on the complexity of understanding complex trigonometric polynomials compared to real trigonometric polynomials. Participants express a preference for real trigonometric polynomials, arguing that they are sufficient for practical applications and questioning the necessity of complex numbers. The conversation highlights that while complex forms can represent Fourier series using exponentials, they may not be needed in real-world scenarios where all values are real. Some users suggest that the use of complex numbers may unnecessarily complicate the understanding of trigonometric polynomials. Ultimately, the dialogue emphasizes the practicality of real trigonometric polynomials over their complex counterparts.
Bob
Messages
28
Reaction score
0
Trigonometric Polynomials...

It's too difficult to understand...

Please tell me how a complex trigonometric polynomial works. I think real trigonometric polynomial is good enough.
T_{N}=\sum^N_{n=0}a_n cos(nx) +i\sum^N_{n=0}a_n*sin(nx)
T_{N} is postion at time x of an object moving along a line. seems have nothing to do with complex numbers.
 
Last edited:
Physics news on Phys.org
I like this one.

T_{N}=\frac{a_0}{2} +\sum^N_{n=0}a_n cos(nx) +\sum^N_{n=0}b_n sin(nx)
 
Last edited:
Bob said:
I like this one.

T_{N}=\frac{a_0}{2} +\sum^N_{n=0}a_n cos(nx) +\sum^N_{n=0}b_n sin(nx)
Do you just want to know how to calculate the coefficients? Look up Fourier series. Hmm.. Now that I think about it this probably didn't help you much, but I can't quite figure out what your question is.
 
Last edited:
I want to know how to use it in practice.
We can find the coefficients and a function f(x) from x0, x1, ...xn and f(x0), f(x1)...f(xn). These values come from observations. I am sure they are not complex numbers. So, the real trigonometric polynomial is good enough. The question is why we use the complex polynomial? Is it only for making things more complicated? :o
 
Bob said:
Trigonometric Polynomials...

It's too difficult to understand...

Please tell me how a complex trigonometric polynomial works. I think real trigonometric polynomial is good enough.
T_{N}=\sum^N_{n=0}a_n cos(nx) +i\sum^N_{n=0}b_n*sin(nx)
T_{N} is postion at time x of an object moving along a line. seems have nothing to do with complex numbers.
(Note: I've changed the second "an" to "bn[/b]". Surely you don't want to use the same notation for two different values.

You don't have to use complex numbers. In fact, in real applications, I've never seen it done. If everything in your application is real, then the bn would have to be imaginary in order to cancel that "i".

The form you give might be used if they were trying to make the point that the Fourier series can be written in terms of exponentials:
T_{N}=\sum^N_{n=0}c_n e^{nix}
where cn is, itself, a complex number.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
8
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K