Fourier Transforms: F[Rect] and F[sinc] Relationship Explanation

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Homework Statement



Explain how F[Rect] = sinc implies F[sinc] = REct +/- a few constants.


Homework Equations



[tex]2\pi f(-w) = \int^{\infty}_{-\infty} F(t) e^{-iwt} dt[/tex]

The Attempt at a Solution



I have no idea!
 
on Phys.org
of which function exactly?
 
I assume rect is short for "rectangle". The question asks you either to prove duality property of continuous Fourier transform or to use it. Search for the duality, you'll see what i mean.