Fractional change in wavelength

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SUMMARY

The discussion focuses on calculating the fractional change in wavelength of light emitted when a hydrogen atom transitions from n=3 to n=2, accounting for the recoil of the atom. The energy difference between the states is calculated using the formula -13.6(1/4 - 1/9). The conservation of momentum is applied to relate the energy of the emitted photon (ΔE) to the recoil velocity (v) of the atom, leading to a quadratic equation in ΔE. Participants confirm that using momentum conservation is the correct approach to solve the problem.

PREREQUISITES
  • Quantum mechanics principles, specifically atomic transitions
  • Understanding of photon energy calculations
  • Knowledge of conservation laws, particularly momentum conservation
  • Familiarity with quadratic equations and their applications in physics
NEXT STEPS
  • Study the derivation of energy levels in hydrogen using the Bohr model
  • Learn about the conservation of momentum in quantum systems
  • Explore the relationship between kinetic energy and photon emission
  • Investigate the implications of recoil in atomic transitions
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Physics students, educators, and anyone interested in quantum mechanics and atomic physics, particularly those studying atomic transitions and photon interactions.

utkarshakash
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Homework Statement


When a photon is emitted from an atom the atom recoils. The kinetic energy of recoil and the energy of photon come from the difference in energies between the states involved in the transition. Suppose a hydrogen atom changes its state from n=3 to n=2. Calculate the fractional change in wavelength of light emitted due to the recoil.

Homework Equations



The Attempt at a Solution



Difference in energies of states = -13.6(1/4 - 1/9)

This is equal to sum of KE of recoil and energy of photon(ΔE).

\dfrac{mv^2}{2} + \delta E = -13.6 \left( 1/4 - 1/9 \right)
From this I can find energy of photon released only if I know the velocity v.
 
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What else might be conserved?
 
haruspex said:
What else might be conserved?

Momentum.
Using momentum conservation I can write

ΔE/c=mv.

Now if I plug v into energy conservation equation. I will get a quadratic in ΔE. Am I on the right track?
 
utkarshakash said:
Momentum.
Using momentum conservation I can write

ΔE/c=mv.

Now if I plug v into energy conservation equation. I will get a quadratic in ΔE. Am I on the right track?

That's what I would do.
 

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