Frames of Reference: Find the speed and heading of the airplane

AI Thread Summary
The discussion revolves around calculating the speed and heading of an airplane using vector addition. The initial calculation of 400 km/h is noted, but participants emphasize the importance of accurately drawing and labeling velocity vectors. A key point is the need for clarity in distinguishing between the wind speed and the airplane's airspeed. The correct heading is established as 45 degrees west of north, and participants suggest that the ground speed must exceed 400 km/h due to the headwind. Overall, the conversation highlights the significance of proper vector representation in solving the problem.
ahira
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Homework Statement
pilot is flying from City A to City B which is 300 km [NW]. If the plane will encounter a constant wind of 80 km/h from the north and the schedule insists that he complete his trip in 0.75 h, what air speed and heading should the plane have?
Relevant Equations
V=d/t
Vg= Vair +Vwing
so far what i have gotten to is that 300/0.75 = 400km/h but I dont know how to draw the diagram for this
 
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would it be like this?
diagram fof.jpg
 
ahira said:
so far what i have gotten to is that 300/0.75 = 400km/h but I dont know how to draw the diagram for this
ahira said:
would it be like this?
'like this' is a good description, but some improvement is in order:
  • heading AB is ##\pi/4##
  • you write ##v_g = v_{air} + v_{wing} ##, but you draw ##v_{wing}= =v_g - v_{air}##. That's fine, but somewhat confusing, especially if you don't label the vectors.
So far, so good; now perform the actual calculation :smile:

##\ ##
 
BvU said:
'like this' is a good description, but some improvement is in order:
  • heading AB is π/4
  • you write vg=vair+vwing, but you draw vwing==vg−vair. That's fine, but somewhat confusing, especially if you don't label the vectors.
So far, so good; now perform the actual calculation :smile:
IMG_3659.jpg

I Changed the diagram and realized that North West sits on an angle of 45 degrees so therefore the angle between the Northline and A should be 45 degrees. I'm not that sure but should the angle at B be 45 degrees as well due to alternate angles ?
 
Last edited:
City A to City B which is 300 km [NW]
So vector AB should correspond to the ground speed with a heading of 45 degrees west of north and magnitude 400 km/h. As you wrote$$v_g = v_{air} + v_{wing}$$but now your drawing shows vector AC (a.k.a.##\ \ v_{wing}\ \ ##) as ##v_g + v_{air}## !!

Lean back a little and use common sense: with a headwind your course should be aiming upwind of A !

And you can also reasonably expect that you need to make more speed than the 400 km/h ('AC should be longer than AB')

##\ ##
 
Sorry for the dumb question, but should ##v_{wing}## be ##v_{wind}## in all of the posts above (including the OP's)?
 
BvU said:
somewhat confusing, especially if you don't label the vectors.
I feel dumb for taking ##v_{air} = ## 80 km/h from the north (the speed OF the air :rolleyes:), when - most likely -@ahira perhaps meant ##v_{air} = ## the speed WRT the air.

So what about
ahira said:
Relevant Equations:
Vg= Vair +Vwing
and the picture in #3 ?

##\ ##
 
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