Relative motion problem with airplane and wind velocity

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Stormblessed
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Homework Statement


A small airplane wants to fly from A to B which is 200 km due south. The wind is blowing towards the east at a velocity of 50 km/h. If the airplane can move through the air at 300 km/h, find the direction the plane should be heading; the speed of the airplane relative to the ground; the time it will take to reach point B.

Homework Equations


p is plane, g is ground, w is wind
Vpg = Vpw + Vwg

The Attempt at a Solution


I wrote out the givens to start:
V = 300 km/h
d = 200 km
Vwg = 50 km/h [E]
Vpg = ?

I do not really know where to go from here. I understand that only one vector with both direction and magnitude is given (Vwg). The velocity of the plane is only a magnitude with no direction. I was unable to draw a vector diagram because I don't know what it should look like to accurately represent the scenario.
 
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So the wind is blowing from the West. The plane will need to fly at an angle west of south.
If that angle is w, then the velocity south will be 300 cos(w) k/h and the velocity west will be 300 sin(w) k/h plus the speed of the wind (-50 k/h).
So you need to make that east/west velocity zero and then work from there.
 
.Scott said:
So the wind is blowing from the West. The plane will need to fly at an angle west of south.
If that angle is w, then the velocity south will be 300 cos(w) k/h and the velocity west will be 300 sin(w) k/h plus the speed of the wind (-50 k/h).
So you need to make that east/west velocity zero and then work from there.

I'm still unsure how to solve it; can you describe the next few steps please?
 
Stormblessed said:
I'm still unsure how to solve it; can you describe the next few steps please?
.Scott said:
Set up the equation for the east/west speed, set it to zero, then solve for cos(w).

I got this equation: 300cos + 300sin - 50 = 0