hold AP 2010
- 3
- 0
When a falling meteoroid is at a distance above the Earth's surface of 3.00 times the Earth's radius, what is its acceleration due to the Earth's gravitation?
The discussion revolves around calculating the acceleration due to Earth's gravity for a meteoroid at a specified distance above the Earth's surface, specifically at three times the Earth's radius. The subject area is gravitational physics.
The discussion is active, with participants providing corrections to each other's reasoning and emphasizing the need for adherence to homework guidelines. There is a recognition of the need for the original poster to demonstrate their understanding and efforts before receiving further assistance.
Participants note the importance of following forum rules regarding homework help, indicating that the original poster has not shown sufficient work or effort in their inquiry.
Denken said:as a rule of thumb the acceleration of gravity on Earth is 9.8m/s ... so unless they want you to do a lot of research i'd say that's it or 32ft/s
Gnosis said:Pardon brno17, but your answer is also incorrect.
The OP stated that a meter is falling from a distance above the Earth's surface of 3 Earth radii, which means a total of 4 Earth radii from the Earth's center of mass. That makes the acceleration by Earth's gravitational field per that distance (4 Earth radii)
<< solution to schoolwork question deleted by berkeman >>