Free vibration in 2DOF spring mass systems

  • Thread starter Thread starter M2H37
  • Start date Start date
  • Tags Tags
    Spring Vibration
Click For Summary
To analyze natural frequencies and mode shapes from a displacement vs time graph in a 2DOF spring mass system, it's essential to understand the relationship between displacement data and system dynamics. Specific exercises or examples can clarify how to interpret these graphs effectively. The discussion emphasizes the need for clear, focused questions to facilitate better assistance. Additionally, the relevance of displacement vs time graphs to the topic is questioned, suggesting a need for further context or clarification. Understanding these concepts is crucial for grasping the fundamentals of free vibration analysis.
M2H37
Messages
1
Reaction score
0
Homework Statement
Identify the experimental value of the natural frequencies and mode shapes using the graphs obtained from the experimental data
Relevant Equations
Unsure
I am completely new to this subject and I am trying to find out how I read data off a displacement vs time graph to find the natural frequencies and mode shapes. Lecturer hasn't provided any materials on graphs, just looking for some help and where to go so I can understand it. Thank you
 
Physics news on Phys.org
Hello @M2H37 ,
:welcome: ##\qquad ##!​

You've come to the right place for help !
For good assistance, it's best to ask answerable questions: we need you to point us in the direction of assistance that is useful for you. The more specific, the better.

In this case: find a typical exercise with a "displacement vs time graph" and point out what it is you don't undestand.

You're new to the subject, so I don't expect a highbrow mathematical approach is appropriate at this point.

##\ ##
 
The statement does not mention anything about displacement versus time graphs. Why do yo think that such graphs are relevant to the question? Is the assignment statement as given in the OP or there is more to it?
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

Similar threads

Replies
17
Views
2K
Replies
3
Views
965
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
4
Views
2K
Replies
11
Views
2K
Replies
39
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K