Frequency and other properties from E-field

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Homework Help Overview

The discussion revolves around a problem involving a plane, harmonic, linearly polarized light wave described by its electric field intensity. Participants are tasked with finding the frequency, wavelength, and index of refraction of the light wave as it travels through glass.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the argument of the cosine function in the electric field equation, questioning the presence of a factor of 2 in front of pi. There are attempts to relate angular frequency and wave number to frequency and wavelength, with some confusion about the velocity of the wave and its implications for the calculations.

Discussion Status

Some participants have provided clarifications regarding the relationships between frequency, wavelength, and wave number. There is an ongoing exploration of the mathematical manipulation of the formula, with no explicit consensus reached on the correct interpretation of the equation.

Contextual Notes

Participants note the importance of adhering to forum policies regarding the demonstration of work and ideas, indicating an awareness of the expectations for homework help discussions.

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Homework Statement



A plane, harmonic, linearly polarized light wave has an electric field intensity given by
{E}_z = {E}_0 cos pi*10^{15}*(t - x/.65c)

while traveling in a piece of glass. Find
(a) The frequency of the light.
(b) Its wavelength.
(c) The index of refraction of the glass.

The Attempt at a Solution



I'm still confused about the argument of the cosine, but I assume that what was within the parenthesis was the real argument. Under this assumption, it fits the form (kx-wt) with some tweaking. The angular frequency w will give me the frequency. I'm pretty sure I need the velocity in order to get the wavelength, and am unsure as to how to find it. Once I get the velocity it will be easy to find the index of refraction.

The problems I ran into:
w=-1 in this case, and so 1/2pi gives me the frequency.
finding velocity of the wave: I used w^{2}/k^{2} = v, however this gives me a value much larger than the speed of light.

Should I just distribute the stuff before the argument? I've never seen a cosine like that. I think that it would be better if it was cos(pi*10^15*(t-x/.65c)) and am confused as to why they didn't do that if that is really what they meant.

Thanks for any help you can provide!
 
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Is there a 2 in front of th e"pi" in the formula?

The wave is in the form
E_z=E_0 cos(\omega t -kx) =E_0 cos(2\pi f t -\frac{2\pi}{\lambda}x) =
=E_0 \cos2\pi f ( t -\frac{x}{v})
where I used
\omega=2\pi f, k=\frac{2\pi}{\lambda}, \lambda=c/f
So v=0.6 c, f=10^15 Hz
 
Last edited:
nasu said:
Is there a 2 in front of th e"pi" in the formula?

Nope, it's just pi. Thank you so much! I didn't know what k equaled. Thanksthanksthanks.
 
Then 2f =10^15.
 
nasu said:
Is there a 2 in front of th e"pi" in the formula?

The wave is in the form
E_z=E_0 cos(\omega t -kx) =E_0 cos(2\pi f t -\frac{2\pi}{\lambda}x) =
=E_0 \cos2\pi f ( t -\frac{x}{v})
where I used
\omega=2\pi f, k=\frac{2\pi}{\lambda}, \lambda=c/f
So v=0.6 c, f=10^15 Hz

Please do not post solutions to homework questions.
 
Sorry if I posted more that I was supposed to.
I am aware that the forum policy requires that the poster shows some work and ideas.
I considered that in this case he showed some start and he is only confused about the math manipulation of the formula.
I'll be more careful in the future.
 
What is K and lambda, can anyone explain please
 

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