Frequency of a standing wave based on slope?

[Ari]

<Moderator's note: Moved from a technical forum and thus no template.>

I've done an experiment on standing waves on a string.
By graphing √T vs λ (where T is tension and λ is wavelength) using the linearized equation √T = (1/√μ) f ⋅ λ, I was able to get this data:
μ = .000256 kg/m
slope = 1.78 N^1/2/m
y - int = 0.1258 √N

My attempt at finding frequency:
y = mx + b
√T = (1/√μ) f ⋅ λ
(√T/λ) = (f/√μ)
f = (√T/λ)(√μ) , in which (√T/λ) = slope

This means that f would equal .02848 (√kg)/s⋅m
which does not make sense both unit or magnitude wise.

Given frequency is 120 Hz. My experimental frequency is .02848 (√kg)/s⋅m

 

[BvU]

Hello Ari,

Please post ini homework. The template there let's you fill in the relevant equation and then you'll see what's going wrong in the math.

 

[Orodruin]

I suggest going through your equations and checking their dimensional consistency until you find where the dimensional inconsistency first appears. Then ask yourself if that equation is correct.